The net gain of ATP in glycolysis is__________.

a)
4

b)
8

c)
2

d)
6

Correct answer is option 'B'. Can you explain this answer?

Question

The net gain of ATP in glycolysis is__________.a)4b)8c)2d)6Correct answer is option 'B'. Can you explain this answer?

Answer

During glycolysis is 2 ATP molecule are used up and 4 ATP molecule are generated. in entire process of glycolysis 2 NADH2 molecule is generated when molecule undergo ETS they will form 3ATP per NADH2 which mean 6 ATP

so totally 10 ATP and 2 ATP is used and be net gain 8

Answer

In glycolysis.....2 ATP is utilised & 4 ATP & 2NADH2 produced....
we know that..; 1NADH2=3 ATP....
therefore;2NADH2=2×3ATP=6 ATP...
Hence;ATP produced in glycolysis =4ATP+6ATP
=10ATP.....
Net gain of ATP=ATP produced - ATP utilised...
=10ATP-2ATP...
=8ATP....
So;option B is true...

Answer

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Answer

Answer

Glycolysis is the first stage of breakdown of glucose in the cell.During Glycolysis 2 ATP molecules are used up and 4 ATP molecules are generated. When theses molecules undergo ETS,they will form 3 ATP per NADH2,which means 6 ATP..Therefore, the total ATP that are forming 10 and as 2 ATP is used up ,the net gain will be 8.
So..the answer is 8.

Answer

Glycolysis is the process of breaking down glucose into pyruvate, which occurs in the cytoplasm of the cell. The net gain of ATP during glycolysis is 2 ATP molecules. Let's break down the process of glycolysis and see how this happens.

Steps of Glycolysis:
1. Glucose is phosphorylated by ATP to form glucose-6-phosphate.
2. Glucose-6-phosphate is converted to fructose-6-phosphate.
3. Fructose-6-phosphate is phosphorylated by ATP to form fructose-1,6-bisphosphate.
4. Fructose-1,6-bisphosphate is broken down into two molecules of glyceraldehyde-3-phosphate (G3P).
5. G3P is oxidized and phosphorylated by NAD+ and ADP to form two molecules of 1,3-bisphosphoglycerate.
6. 1,3-bisphosphoglycerate is converted to 3-phosphoglycerate.
7. 3-phosphoglycerate is converted to 2-phosphoglycerate.
8. 2-phosphoglycerate is converted to phosphoenolpyruvate (PEP).
9. PEP is converted to pyruvate and ATP is produced.

During steps 1-5 of glycolysis, 2 ATP molecules are used up. However, during step 5, NAD+ is reduced to NADH, which can be used to produce ATP in the electron transport chain. Additionally, during step 9, 2 ATP molecules are produced. Therefore, the net gain of ATP during glycolysis is 2 ATP molecules.

Answer

8 ATP
2 ATP and 2 NADH2 molecules are produced at the end of glycolysis, as we know... 1 NADH2 molecule= 3 ATP
so, 2+ 2×3= 2+6=8

Answer

Answer

During glycolysis 2 ATP'S are used and 2 NADH2 and 4ATP'S are  formed ..so net gain 8ATP'S..

Answer

Glycolysis is the process of breaking down glucose into pyruvate molecules. It takes place in the cytoplasm of cells and is the first stage of cellular respiration. During glycolysis, a net gain of ATP is produced.

Explanation:

The net gain of ATP during glycolysis is 2. This means that two molecules of ATP are produced during glycolysis, but four molecules are actually produced while two are used up in the process. The steps involved in glycolysis are:

1. Glucose is converted to glucose-6-phosphate by the enzyme hexokinase. This reaction requires the input of one molecule of ATP.

2. Glucose-6-phosphate is converted to fructose-6-phosphate by the enzyme phosphohexose isomerase.

3. Fructose-6-phosphate is converted to glyceraldehyde-3-phosphate and dihydroxyacetone phosphate by the enzyme aldolase.

4. Dihydroxyacetone phosphate is converted to glyceraldehyde-3-phosphate by the enzyme triose phosphate isomerase.

5. Glyceraldehyde-3-phosphate is converted to 1,3-bisphosphoglycerate by the enzyme glyceraldehyde-3-phosphate dehydrogenase. During this reaction, two molecules of NADH are produced.

6. 1,3-bisphosphoglycerate is converted to 3-phosphoglycerate by the enzyme phosphoglycerate kinase. This reaction produces two molecules of ATP.

7. 3-phosphoglycerate is converted to 2-phosphoglycerate by the enzyme phosphoglycerate mutase.

8. 2-phosphoglycerate is converted to phosphoenolpyruvate by the enzyme enolase.

9. Phosphoenolpyruvate is converted to pyruvate by the enzyme pyruvate kinase. This reaction produces two molecules of ATP.

Thus, the net gain of ATP during glycolysis is 2 (4 ATP produced - 2 ATP used). The NADH produced during glycolysis can be used in the electron transport chain to produce additional ATP molecules through oxidative phosphorylation.

Answer

In glycolysis  4 ATP are produce and 2 lost so net gain is 2 ATP.

Answer

The net gain is 2 ATP AND 2 NADH2 AFTER ETS EACH NADH2 GIVES 3 ATP HENCE THE NET GAIN IN GLYCOLYSIS IS 8 ATP

Answer

Answer mustbe 2(option-C) as NADPH are used to synthesise ATP during ETS and not obtained as a direct product of glycolysis.Even it depends on shuttle system whether the NADPH synthesised during glycolysis leads to 4 or 6 ATP molecules during ETS so either 6 or 8 net ATP may be formed(according to questioner's view).

Answer

Option B : 8

Answer

During glycolysis :
Two NADH are generated at 5th step( 1 NADH= 3 ATP). Hence 2
NADH gives 6 ATP.

2 ATP are generated at 6th step ( conversion of 1,3 bisphosphiglyceric acid to 3 - phosphoglyceric acid)

Again 2 ATP are generated at 9th step (i.e. from phosphoenolpyruvte to pyruvic acid)

HENCE IF WE ADD THEM WE GET 10 ATPs WHICH ARE GENERATED IN GLYCOLYSIS....

Now count the number of ATP CONSUMED :

1 ATP is consumed at 1st step ( conversion of glucose to glucose 6 phosphate).

1 ATP is consumed at 3rd step (i.e. fructose 6 phosphate to fructose 1,6 phosphate)

THUS TOTAL NO. OF ATP CONSUMED ARE 2.

THE NET GAIN WILL BE :
NO. OF ATP GENERATED - NO.OF ATP CONSUMED
i.e. 10 -2= 8
THE NET GAIN IS 8 ATPs.

Answer

In glycolysis we get total ATP =10
6 from NADH and 4 as substrate level phosporylation.
in these 10 , 2 are utilised in initial steps of glycolysis
so,net gain =10 - 2 = 8

Answer

Answer

4 ATP and 2 NADPH are produced in glycolysis.
1 NADPH-3ATP.
So 4+2×3=10.
out of 10,2 ATP are consumed in the process.
so net gain is 8.

Answer

Is it talking about including NADH2 i think the ans. should be 2

Answer

To everyone saying it's 8, the question asks the net gain DURING glycolysis. NADH2 does not yield 3 ATP in glycolysis itself, but in ETS. So in my opinion, the answer should've been 2, because that's the net ATP due to Substrate Level Phosphorylation that happens on site during glycolysis. The rest 6 ATP is earned due to Oxidative Phosphorylation during ETS

Answer

8 atp

Answer

Correct answer is C because glyocolysis occurs in anaerobic animal like yeast

Answer

B) 2

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