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A conducting rod of length a is rotating with constant angular speed ω about its perpendicular bisector. A uniform magnetic field B exist parallel to the axis of rotation. The emf induced between two ends of the rod is.
  • a)
  • b)
    0
  • c)
  • d)
    Bωa2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A conducting rod of lengthais rotating with constant angular speed&ome...
Let us calculate motional emf produced in the rod. Consider a unit positive charge on the rod at a distance r  from the centre. Let rod rotates with angular velocity ω. Velocity of this unit positive charge in magnetic field in transverse direction is ωr.
Lorentz force acting on the unit charge
Potential difference between A  and  O = VAO
work done in moving a unit positive charge from O  to A.
The correct answer is:  
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Most Upvoted Answer
A conducting rod of lengthais rotating with constant angular speed&ome...
Let us calculate motional emf produced in the rod. Consider a unit positive charge on the rod at a distance r  from the centre. Let rod rotates with angular velocity ω. Velocity of this unit positive charge in magnetic field in transverse direction is ωr.
Lorentz force acting on the unit charge
Potential difference between A  and  O = VAO
work done in moving a unit positive charge from O  to A.
The correct answer is:  
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A conducting rod of lengthais rotating with constant angular speedωabout its perpendicular bisector. A uniform magnetic fieldBexist parallel to the axis of rotation. The emf induced between two ends of the rod is.a)b)0c)d)Bωa2Correct answer is option 'C'. Can you explain this answer?
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