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The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. The smallest angle of Bragg scattering for 0.03 nm X -ray is (in degrees)
Correct answer is '5.8'. Can you explain this answer?
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The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. Th...
The correct answer is: 5.8
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The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. Th...
Given:
- Distance between adjacent atomic planes in CaCO3 = 0.3 nm
- Wavelength of X-ray = 0.03 nm
To Find:
- Smallest angle of Bragg scattering
Explanation:
The Bragg's law relates the wavelength of incident X-ray radiation to the interplanar spacing of the crystal lattice and the angle of scattering. It can be given as:
nλ = 2d sinθ
Where,
- n is the order of the diffraction peak (usually 1 for the first peak)
- λ is the wavelength of the X-ray radiation
- d is the interplanar spacing of the crystal lattice
- θ is the angle of scattering
In this case, we are given the interplanar spacing (d = 0.3 nm) and the wavelength of X-ray (λ = 0.03 nm). We need to find the smallest angle of Bragg scattering (θ).
Calculation:
Using Bragg's law, we can rearrange the equation to solve for sinθ:
sinθ = nλ / (2d)
Plugging in the values, we get:
sinθ = (1 * 0.03 nm) / (2 * 0.3 nm)
sinθ = 0.015 / 0.6
sinθ = 0.025
To find θ, we can take the inverse sine (sin⁻¹) of the value:
θ = sin⁻¹(0.025)
Using a calculator, we find:
θ ≈ 1.44°
However, this is the angle for the first order of diffraction (n=1). The question asks for the smallest angle of Bragg scattering, so we need to consider the zeroth order (n=0) as well.
For the zeroth order, n=0 and sinθ=0. This means that the angle of scattering is 0°.
Therefore, the smallest angle of Bragg scattering is 0°, not 5.8° as mentioned in the answer. It seems there might be an error in the given correct answer.
- Distance between adjacent atomic planes in CaCO3 = 0.3 nm
- Wavelength of X-ray = 0.03 nm
To Find:
- Smallest angle of Bragg scattering
Explanation:
The Bragg's law relates the wavelength of incident X-ray radiation to the interplanar spacing of the crystal lattice and the angle of scattering. It can be given as:
nλ = 2d sinθ
Where,
- n is the order of the diffraction peak (usually 1 for the first peak)
- λ is the wavelength of the X-ray radiation
- d is the interplanar spacing of the crystal lattice
- θ is the angle of scattering
In this case, we are given the interplanar spacing (d = 0.3 nm) and the wavelength of X-ray (λ = 0.03 nm). We need to find the smallest angle of Bragg scattering (θ).
Calculation:
Using Bragg's law, we can rearrange the equation to solve for sinθ:
sinθ = nλ / (2d)
Plugging in the values, we get:
sinθ = (1 * 0.03 nm) / (2 * 0.3 nm)
sinθ = 0.015 / 0.6
sinθ = 0.025
To find θ, we can take the inverse sine (sin⁻¹) of the value:
θ = sin⁻¹(0.025)
Using a calculator, we find:
θ ≈ 1.44°
However, this is the angle for the first order of diffraction (n=1). The question asks for the smallest angle of Bragg scattering, so we need to consider the zeroth order (n=0) as well.
For the zeroth order, n=0 and sinθ=0. This means that the angle of scattering is 0°.
Therefore, the smallest angle of Bragg scattering is 0°, not 5.8° as mentioned in the answer. It seems there might be an error in the given correct answer.
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The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. The smallest angle of Bragg scattering for 0.03 nm X -ray is (in degrees)Correct answer is '5.8'. Can you explain this answer?
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The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. The smallest angle of Bragg scattering for 0.03 nm X -ray is (in degrees)Correct answer is '5.8'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. The smallest angle of Bragg scattering for 0.03 nm X -ray is (in degrees)Correct answer is '5.8'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The distance between the adjacent atomic planes in CaCO3 is 0.3 nm. The smallest angle of Bragg scattering for 0.03 nm X -ray is (in degrees)Correct answer is '5.8'. Can you explain this answer?.
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