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The average kinetic energy of a gas molecules at 27°C is 6.21x1021 J. Its average kinetic energy at 227°C will bea)52.2x1021 Jb)5.22x1021 Jc)10.35x1021 Jd)11.35x1021 JCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The average kinetic energy of a gas molecules at 27°C is 6.21x1021 J. Its average kinetic energy at 227°C will bea)52.2x1021 Jb)5.22x1021 Jc)10.35x1021 Jd)11.35x1021 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average kinetic energy of a gas molecules at 27°C is 6.21x1021 J. Its average kinetic energy at 227°C will bea)52.2x1021 Jb)5.22x1021 Jc)10.35x1021 Jd)11.35x1021 JCorrect answer is option 'C'. Can you explain this answer?.

Solutions for The average kinetic energy of a gas molecules at 27°C is 6.21x1021 J. Its average kinetic energy at 227°C will bea)52.2x1021 Jb)5.22x1021 Jc)10.35x1021 Jd)11.35x1021 JCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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