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CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3?
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CsBr crystallises in a body centred cubic lattice. The unit cell lengt...
Calculating Density of CsBr

Given:

Lattice Type: Body Centred Cubic

Unit Cell Length: 436.6 pm

Atomic Mass of Cs: 133 amu

Atomic Mass of Br: 80 amu

Avogadro Number: 6.02 x 10^23 /mol


To Find: Density of CsBr


Solution:


Step 1: Calculate the volume of the unit cell.

Volume of a BCC unit cell = (4r/√3)³

where r is the radius of the atom.

Here, unit cell length = 436.6 pm = 4.366 Å

Radius of Cs atom = (1/2) x 4.366 Å = 2.183 Å

Radius of Br atom = (1/2) x 4.366 Å = 2.183 Å

Volume of the unit cell = (4 x 2.183 Å / √3)³ = 38.78 ų


Step 2: Calculate the mass of one unit cell.

Mass of one unit cell = (mass of Cs atom + mass of Br atom)

= (133 amu + 80 amu) / (6.02 x 10^23)

= 3.53 x 10^-22 g


Step 3: Calculate the density of CsBr.

Density of CsBr = (mass of one unit cell) / (volume of one unit cell)

= (3.53 x 10^-22 g) / (38.78 ų x (1 cm / 10^-8 Å)³)

= 4.25 g/cm³


Answer: The density of CsBr is 4.25 g/cm³. Therefore, the correct option is (A) 4.25 g/cm³.
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CsBr crystallises in a body centred cubic lattice. The unit cell lengt...
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CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3?
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CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3?.
Solutions for CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? defined & explained in the simplest way possible. Besides giving the explanation of CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3?, a detailed solution for CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? has been provided alongside types of CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? theory, EduRev gives you an ample number of questions to practice CsBr crystallises in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs =133 and that of Br=80 amu and Avogadro number being 6.02×1023 /mol the density of CsBr is (A)4.25 g/cm 3 (B) 42.5 g/cm3 (C) 0.42 g /cm3 (C)8.25 g/cm 3? tests, examples and also practice NEET tests.
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