A horizontal platform executes up and clown S.H.M. about a mean positi...
Here if R = normal reaction then R-mg
= -mg
or R = mg-ma = m(g-a)
Also Max. acceleration a= Aω
2∴ R = mg - mAω
2For object, not to leave the platform R = 0
∴ mg = - mAω
2
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A horizontal platform executes up and clown S.H.M. about a mean positi...
Here if R = normal reaction then R-mg
= -mg
or R = mg-ma = m(g-a)
Also Max. acceleration a= Aω
2∴ R = mg - mAω
2For object, not to leave the platform R = 0
∴ mg = - mAω
2
A horizontal platform executes up and clown S.H.M. about a mean positi...
The period of a simple harmonic motion (SHM) is the time taken for one complete cycle of the motion. In this case, the period of the horizontal platform executing SHM is given as 2 units of time.
This means that it takes 2 units of time for the platform to go through one complete cycle of oscillation. In other words, it takes 2 units of time for the platform to move from its initial position, reach its maximum displacement in one direction, return to its initial position, reach its maximum displacement in the opposite direction, and finally return to its initial position again.
During this period of 2 units of time, the platform will go through all the phases of SHM, including moving away from the mean position, reaching the maximum displacement, moving back towards the mean position, passing through the mean position, moving away from the mean position in the opposite direction, reaching the maximum displacement in the opposite direction, moving back towards the mean position again, and finally passing through the mean position to complete one cycle.
The frequency of the SHM can be calculated by taking the reciprocal of the period. In this case, the frequency would be 1/2 units of time, which means that the platform completes one cycle of oscillation every 1/2 unit of time.
It's important to note that in SHM, the mean position refers to the equilibrium position of the platform, where the net force acting on it is zero.