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Using the illustration from the previous question, what would be the IP address of S0 if you were using the first subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. Again, the zero subnet should not be considered valid for this question.
- a)192.168.10.24
- b)192.168.10.62
- c)192.168.10.30
- d)192.168.10.127
Correct answer is option 'C'. Can you explain this answer?
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Using the illustration from the previous question, what would be the I...
A /28 is a 255.255.255.240 mask. The first subnet is 16 (remember that the question stated not to use subnet zero) and the next subnet is 32, so our broadcast address is 31. This makes our host range 17-30. 30 is the last valid host.
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Using the illustration from the previous question, what would be the I...
To determine the IP address of S0 using the first subnet, we need to consider the network ID and the range of available IP addresses within that subnet.
Given:
Network ID: 192.168.10.0/28
Last available IP address in the range is required.
Understanding the Subnet Mask:
The subnet mask /28 means that the first 28 bits are used to define the network ID, and the remaining 4 bits are used for host addresses within that network. In binary, the subnet mask would be 11111111.11111111.11111111.11110000.
Determining the Network ID and Range:
The network ID is obtained by applying the subnet mask to the given IP address. Let's convert the IP address to binary and apply the subnet mask:
IP address: 192.168.10.0
Binary: 11000000.10101000.00001010.00000000
Subnet Mask: 11111111.11111111.11111111.11110000
Network ID: 11000000.10101000.00001010.00000000 (192.168.10.0)
The range of available IP addresses within this subnet can be determined by substituting all the host bits with 1s. The last available IP address will have all 4 host bits set to 1.
Range of IP addresses: 192.168.10.0001 (0001 = 1 in binary) to 192.168.10.1110 (1110 = 14 in binary)
Finding the Last Available IP Address:
Since we are looking for the last available IP address in the range, we need to consider the IP address with the highest value for the host bits. In this case, the host bits are 0001. By substituting all the host bits with 1s, we get:
IP address: 192.168.10.1110 (1110 = 14 in binary)
Therefore, the IP address of S0 using the first subnet is 192.168.10.14.
However, none of the provided answer choices match this IP address. Therefore, it seems there may be an error in the options given or in the question itself.
Given:
Network ID: 192.168.10.0/28
Last available IP address in the range is required.
Understanding the Subnet Mask:
The subnet mask /28 means that the first 28 bits are used to define the network ID, and the remaining 4 bits are used for host addresses within that network. In binary, the subnet mask would be 11111111.11111111.11111111.11110000.
Determining the Network ID and Range:
The network ID is obtained by applying the subnet mask to the given IP address. Let's convert the IP address to binary and apply the subnet mask:
IP address: 192.168.10.0
Binary: 11000000.10101000.00001010.00000000
Subnet Mask: 11111111.11111111.11111111.11110000
Network ID: 11000000.10101000.00001010.00000000 (192.168.10.0)
The range of available IP addresses within this subnet can be determined by substituting all the host bits with 1s. The last available IP address will have all 4 host bits set to 1.
Range of IP addresses: 192.168.10.0001 (0001 = 1 in binary) to 192.168.10.1110 (1110 = 14 in binary)
Finding the Last Available IP Address:
Since we are looking for the last available IP address in the range, we need to consider the IP address with the highest value for the host bits. In this case, the host bits are 0001. By substituting all the host bits with 1s, we get:
IP address: 192.168.10.1110 (1110 = 14 in binary)
Therefore, the IP address of S0 using the first subnet is 192.168.10.14.
However, none of the provided answer choices match this IP address. Therefore, it seems there may be an error in the options given or in the question itself.
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Using the illustration from the previous question, what would be the IP address of S0 if you were using the first subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. Again, the zero subnet should not be considered valid for this question.a)192.168.10.24b)192.168.10.62c)192.168.10.30d)192.168.10.127Correct answer is option 'C'. Can you explain this answer?
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