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Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN?
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Two plates are fastened by means of two bolts as shown in figure. The ...
Solution:
Given data:
Syt = 400 N/mm2
Factor of safety = 5
People = 5 KN
We have to determine the size of the bolt that can withstand the given load and factor of safety.
Calculation:
The maximum load that can be withstood by the bolt can be calculated using the formula:
σallowable = Syt / FoS
where,
σallowable = allowable stress
Syt = tensile strength of the material
FoS = factor of safety
Substituting the given values, we get:
σallowable = 400 / 5 = 80 N/mm2
The cross-sectional area of the bolt required can be calculated using the formula:
A = People / σallowable
where,
A = cross-sectional area of the bolt
People = applied load
Substituting the given values, we get:
A = 5 / 80 = 0.0625 cm2
Assuming a standard bolt size of M6, the cross-sectional area of the bolt can be calculated as:
A = π/4 x d2
where,
d = diameter of the bolt
Substituting the values, we get:
0.0625 = π/4 x d2
d2 = 0.0625 x 4 / π
d = 0.28 cm or 2.8 mm (approx.)
Therefore, a bolt of size M6 can withstand the given load and factor of safety.
Explanation:
The given problem is related to bolted joints used in mechanical engineering. Bolted joints are used to connect two or more parts together. The bolts used in these joints are subjected to axial tensile loads. The force acting on the bolt can be calculated using the load applied and the cross-sectional area of the bolt. The bolt should be designed to withstand the maximum load that can be applied to it. The tensile strength of the material used for the bolt is also an important factor in the design. The factor of safety is used to ensure that the bolt can withstand the applied load without failure. The allowable stress is calculated using the tensile strength and factor of safety. The cross-sectional area of the bolt required to withstand the load can be calculated using the allowable stress and applied load. The size of the bolt can be determined using the cross-sectional area and assuming a standard bolt size.
Given data:
Syt = 400 N/mm2
Factor of safety = 5
People = 5 KN
We have to determine the size of the bolt that can withstand the given load and factor of safety.
Calculation:
The maximum load that can be withstood by the bolt can be calculated using the formula:
σallowable = Syt / FoS
where,
σallowable = allowable stress
Syt = tensile strength of the material
FoS = factor of safety
Substituting the given values, we get:
σallowable = 400 / 5 = 80 N/mm2
The cross-sectional area of the bolt required can be calculated using the formula:
A = People / σallowable
where,
A = cross-sectional area of the bolt
People = applied load
Substituting the given values, we get:
A = 5 / 80 = 0.0625 cm2
Assuming a standard bolt size of M6, the cross-sectional area of the bolt can be calculated as:
A = π/4 x d2
where,
d = diameter of the bolt
Substituting the values, we get:
0.0625 = π/4 x d2
d2 = 0.0625 x 4 / π
d = 0.28 cm or 2.8 mm (approx.)
Therefore, a bolt of size M6 can withstand the given load and factor of safety.
Explanation:
The given problem is related to bolted joints used in mechanical engineering. Bolted joints are used to connect two or more parts together. The bolts used in these joints are subjected to axial tensile loads. The force acting on the bolt can be calculated using the load applied and the cross-sectional area of the bolt. The bolt should be designed to withstand the maximum load that can be applied to it. The tensile strength of the material used for the bolt is also an important factor in the design. The factor of safety is used to ensure that the bolt can withstand the applied load without failure. The allowable stress is calculated using the tensile strength and factor of safety. The cross-sectional area of the bolt required to withstand the load can be calculated using the allowable stress and applied load. The size of the bolt can be determined using the cross-sectional area and assuming a standard bolt size.
Community Answer
Two plates are fastened by means of two bolts as shown in figure. The ...
Shear strength = 0.5Syt = 200N/mm2
allowable shear=200/fos=40
Load/(2*Ac)=40
5000/(2*40)=Ac
Ac= 62.5 mm2
Ac= (πd^2)/4
d=8.9mm
allowable shear=200/fos=40
Load/(2*Ac)=40
5000/(2*40)=Ac
Ac= 62.5 mm2
Ac= (πd^2)/4
d=8.9mm
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Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN?
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Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN?.
Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two plates are fastened by means of two bolts as shown in figure. The bolt are made of plain carbon steel 30C8( Syt = 400 N/mm2) and the factor of safety is 5 determine the size of the bolt if People=5KN?.
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