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The probability that a non leap year selected at random will contain 53 Sunday's is
  • a)
    1/7
  • b)
    2/7
  • c)
    3/7
  • d)
    5/7
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The probability that a non leap year selected at random will contain 5...
A non-leap year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364 days .
365– 364 = 1 day extra.
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday, Saturday, Sunday.
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 sundays = 1/7.
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Community Answer
The probability that a non leap year selected at random will contain 5...
A non leap year has 365 days,
a year has 52 week, hence there will be 52 Sundays for sure.
52 weeks=52×7=364 days,
in a non leap year there will be 52 Sundays and one day will be left.
this one day can be Sunday Monday, Tuesday Wednesday ,Thursday, Friday ,Saturday , Sunday.
out of all the 7 outcomes the favourable outcome is 1
so,the probability that a non leap year selected at random will contain 53 Sundays=1/7
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The probability that a non leap year selected at random will contain 53 Sundays isa)1/7b)2/7c)3/7d)5/7Correct answer is option 'A'. Can you explain this answer?
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