What should be added to the polynomial x power3-3xpower2 6x-15 so that...
Solution:
Divisibility Rule:
If a polynomial P(x) is completely divisible by (x-a), then P(a) = 0.
Given Polynomial:
P(x) = x³ - 3x² + 6x - 15
Divisibility by x-3:
To check if P(x) is completely divisible by (x-3), we need to check whether P(3) = 0 or not.
P(3) = (3)³ - 3(3)² + 6(3) - 15
= 27 - 27 + 18 - 15
= 3
Since P(3) ≠ 0, P(x) is not completely divisible by (x-3).
Adding a Term:
To make P(x) completely divisible by (x-3), we need to add a term of the form (x-a) where a = 3.
Let Q(x) = P(x) + (x-3) = x³ - 3x² + 6x - 15 + x - 3
= x³ - 3x² + 7x - 18
Divisibility by x-3:
To check if Q(x) is completely divisible by (x-3), we need to check whether Q(3) = 0 or not.
Q(3) = (3)³ - 3(3)² + 7(3) - 18
= 27 - 27 + 21 - 18
= 3
Since Q(3) = 0, Q(x) is completely divisible by (x-3).
Therefore, the term (x-3) should be added to the polynomial x³ - 3x² + 6x - 15 to make it completely divisible by (x-3).