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What should be added to the polynomial x power3-3xpower2 6x-15 so that it completely divisible by x-3?
Most Upvoted Answer
What should be added to the polynomial x power3-3xpower2 6x-15 so that...
The remainder when f(x) is divided by (x-a)
is f(a)
Let f(x)= x³-3x² +6x-15
The remainder when f(x) is divided by (x-3)
=f(3)
=(3)³-3(3)² +6(3)-15
=27-27+18-15
=3
Therefore -3 should be added to the given polynomial so that it is exactly divisible by (x-3).
Community Answer
What should be added to the polynomial x power3-3xpower2 6x-15 so that...
Solution:


Divisibility Rule:

If a polynomial P(x) is completely divisible by (x-a), then P(a) = 0.

Given Polynomial:

P(x) = x³ - 3x² + 6x - 15

Divisibility by x-3:

To check if P(x) is completely divisible by (x-3), we need to check whether P(3) = 0 or not.

P(3) = (3)³ - 3(3)² + 6(3) - 15
= 27 - 27 + 18 - 15
= 3

Since P(3) ≠ 0, P(x) is not completely divisible by (x-3).

Adding a Term:

To make P(x) completely divisible by (x-3), we need to add a term of the form (x-a) where a = 3.

Let Q(x) = P(x) + (x-3) = x³ - 3x² + 6x - 15 + x - 3
= x³ - 3x² + 7x - 18

Divisibility by x-3:

To check if Q(x) is completely divisible by (x-3), we need to check whether Q(3) = 0 or not.

Q(3) = (3)³ - 3(3)² + 7(3) - 18
= 27 - 27 + 21 - 18
= 3

Since Q(3) = 0, Q(x) is completely divisible by (x-3).

Therefore, the term (x-3) should be added to the polynomial x³ - 3x² + 6x - 15 to make it completely divisible by (x-3).
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What should be added to the polynomial x power3-3xpower2 6x-15 so that it completely divisible by x-3?
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