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The cartesian product A×A has 9 elements among which are found (-1,0) and(0,1). Find the set A and the remaining elements of A×A?
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The cartesian product A×A has 9 elements among which are found (-1,0) ...
We know A x A=9 elements
this shows A has elements (3x3=9)

AxA contains (-1,0) (0,1)
So (-1,0) is in set A
-1 and 0 is in set A ---(i)

Similiarly, (0,1) is in Set A
so, 0 and 1 is in set A ---(ii)

from i and ii equations, we know the 3 elements of set A are 1,0 ,-1

ATQ, setA×SetA
={-1,0,1}×{-1,0,1}
So the remaining elements are = (-1,1) (0,-1) (-1,1) (0,0) (1,-1) (1,0) (1,1)
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The cartesian product A×A has 9 elements among which are found (-1,0) ...
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The cartesian product A×A has 9 elements among which are found (-1,0) and(0,1). Find the set A and the remaining elements of A×A?
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