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A block of mass 4kg is kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30N is applied parallel to the ground. The resultant force (in N) exerted by the ground on the block is : (g =10 m/s2)
Correct answer is '50'. Can you explain this answer?
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A block of mass 4kgis kept on ground. The coefficient of friction betw...
The correct answer is: 50
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A block of mass 4kgis kept on ground. The coefficient of friction betw...
Given:
Mass of the block (m) = 4 kg
Coefficient of friction (μ) = 0.80
External force (F) = 30 N
Acceleration due to gravity (g) = 10 m/s²
Explanation:
Step 1: Calculate the force of friction:
Frictional force (Ffriction) = μ * Normal force
The normal force (Fn) is equal to the weight of the block, which can be calculated as:
Fn = m * g
Substituting the values, we get:
Fn = 4 kg * 10 m/s² = 40 N
Now, substituting the value of Fn into the equation for frictional force, we get:
Ffriction = 0.80 * 40 N = 32 N
Step 2: Determine the net force:
Net force (Fnet) = External force - Frictional force
Substituting the given values, we get:
Fnet = 30 N - 32 N = -2 N
The negative sign indicates that the net force is acting in the opposite direction of the external force.
Step 3: Calculate the resultant force exerted by the ground:
The resultant force exerted by the ground (Fground) can be calculated using Newton's second law:
Fground = Fn + Fnet
Substituting the values, we get:
Fground = 40 N + (-2 N) = 38 N
Step 4: Correcting for the negative sign:
The negative sign indicates that the force exerted by the ground is in the opposite direction to the applied force. However, the question asks for the magnitude of the resultant force, which is always positive. Therefore, we need to take the absolute value of the resultant force:
|Fground| = |38 N| = 38 N
Step 5: Final answer:
The magnitude of the resultant force exerted by the ground on the block is 38 N. However, since the question specifies that the correct answer is 50 N, it is likely that there was an error in the given values or calculation.
Mass of the block (m) = 4 kg
Coefficient of friction (μ) = 0.80
External force (F) = 30 N
Acceleration due to gravity (g) = 10 m/s²
Explanation:
Step 1: Calculate the force of friction:
Frictional force (Ffriction) = μ * Normal force
The normal force (Fn) is equal to the weight of the block, which can be calculated as:
Fn = m * g
Substituting the values, we get:
Fn = 4 kg * 10 m/s² = 40 N
Now, substituting the value of Fn into the equation for frictional force, we get:
Ffriction = 0.80 * 40 N = 32 N
Step 2: Determine the net force:
Net force (Fnet) = External force - Frictional force
Substituting the given values, we get:
Fnet = 30 N - 32 N = -2 N
The negative sign indicates that the net force is acting in the opposite direction of the external force.
Step 3: Calculate the resultant force exerted by the ground:
The resultant force exerted by the ground (Fground) can be calculated using Newton's second law:
Fground = Fn + Fnet
Substituting the values, we get:
Fground = 40 N + (-2 N) = 38 N
Step 4: Correcting for the negative sign:
The negative sign indicates that the force exerted by the ground is in the opposite direction to the applied force. However, the question asks for the magnitude of the resultant force, which is always positive. Therefore, we need to take the absolute value of the resultant force:
|Fground| = |38 N| = 38 N
Step 5: Final answer:
The magnitude of the resultant force exerted by the ground on the block is 38 N. However, since the question specifies that the correct answer is 50 N, it is likely that there was an error in the given values or calculation.
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A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer?
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A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer?.
A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer?.
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A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer?, a detailed solution for A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer? has been provided alongside types of A block of mass 4kgis kept on ground. The coefficient of friction between the block and the ground is 0.80. An external force of magnitude 30Nis applied parallel to the ground. The resultant force (inN) exerted by the ground on the block is : (g=10m/s2)Correct answer is '50'. Can you explain this answer? theory, EduRev gives you an
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