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A force F = t is applied to a block A as shown in figure, where t is time in seconds. The force is applied at t = 0 seconds when the system was at rest. Which of the following graph correctly give the frictional force between A and horizontal surface as a function of time t. [Assume that at t = 0, tension in the string connecting the two blocks is zero].
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A forceF=tis applied to a blockAas shown in figure, wheretis time inse...
Let mA and mB be the mass of blocks A and B respectively.
As the force F increases from 0 to µs mAg, the frictional force f on block A is such that f = F. When F = µsmAg, the frictional force f attains maximum value f = µsmg.
As F is further increased to µs(mA + mB)g, the block A does not move. In this duration frictional force on block A remains constant at µsmAg.
As F further increased, system will start moving and kinetic friction (µxAg) will start acting on A (µsk). Hence C is correct choice.
The correct answer is:
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Most Upvoted Answer
A forceF=tis applied to a blockAas shown in figure, wheretis time inse...
Let mA and mB be the mass of blocks A and B respectively.
As the force F increases from 0 to µs mAg, the frictional force f on block A is such that f = F. When F = µsmAg, the frictional force f attains maximum value f = µsmg.
As F is further increased to µs(mA + mB)g, the block A does not move. In this duration frictional force on block A remains constant at µsmAg.
As F further increased, system will start moving and kinetic friction (µxAg) will start acting on A (µsk). Hence C is correct choice.
The correct answer is:
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A forceF=tis applied to a blockAas shown in figure, wheretis time inseconds. The force is applied att= 0secondswhen the system was at rest. Which of the following graph correctly give the frictional force betweenAand horizontal surface as a function of timet. [Assume that att= 0, tension in the string connecting the two blocks is zero].a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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