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The solubility of Ca3(PO4)2 in water is y moles / litre. Its solubility product is
- a)6y4
- b)36y4
- c)64y5
- d)108y5
Correct answer is option 'D'. Can you explain this answer?
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The solubility of Ca3(PO4)2 in water is y moles / litre. Its solubilit...
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The solubility of Ca3(PO4)2 in water is y moles / litre. Its solubilit...
The solubility product (Ksp) is a measure of the equilibrium between a solid compound and its ions in a saturated solution. It represents the product of the concentrations of the ions in the solution, each raised to the power of their stoichiometric coefficients. In the case of Ca3(PO4)2, the solubility product can be determined by the following equation:
Ca3(PO4)2(s) ⇌ 3Ca2+(aq) + 2PO43-(aq)
The solubility of Ca3(PO4)2 in water is given as y moles per liter. This means that at equilibrium, the concentration of Ca2+ ions will be 3y moles per liter, and the concentration of PO43- ions will be 2y moles per liter.
To find the solubility product, we multiply the concentrations of the ions raised to the power of their stoichiometric coefficients:
Ksp = [Ca2+]^3 * [PO43-]^2
Substituting the concentrations we found above:
Ksp = (3y)^3 * (2y)^2
Simplifying the expression:
Ksp = 27y^3 * 4y^2
Ksp = 108y^5
Therefore, the correct answer is option 'D', 108y^5.
In summary, the solubility product of Ca3(PO4)2 in water is given by the expression 108y^5. This represents the equilibrium between the solid compound and its ions in a saturated solution, with the concentrations of Ca2+ and PO43- ions determined by the solubility of Ca3(PO4)2.
Ca3(PO4)2(s) ⇌ 3Ca2+(aq) + 2PO43-(aq)
The solubility of Ca3(PO4)2 in water is given as y moles per liter. This means that at equilibrium, the concentration of Ca2+ ions will be 3y moles per liter, and the concentration of PO43- ions will be 2y moles per liter.
To find the solubility product, we multiply the concentrations of the ions raised to the power of their stoichiometric coefficients:
Ksp = [Ca2+]^3 * [PO43-]^2
Substituting the concentrations we found above:
Ksp = (3y)^3 * (2y)^2
Simplifying the expression:
Ksp = 27y^3 * 4y^2
Ksp = 108y^5
Therefore, the correct answer is option 'D', 108y^5.
In summary, the solubility product of Ca3(PO4)2 in water is given by the expression 108y^5. This represents the equilibrium between the solid compound and its ions in a saturated solution, with the concentrations of Ca2+ and PO43- ions determined by the solubility of Ca3(PO4)2.
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The solubility of Ca3(PO4)2 in water is y moles / litre. Its solubility product isa)6y4b)36y4c)64y5d)108y5Correct answer is option 'D'. Can you explain this answer?
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