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A 4.5 cm needle placed 12cm away from convex mirror of focal length 15cm. Give the location of image and magnification. Describe what happens to the image as the needle is moved farther from the mirror.?
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A 4.5 cm needle placed 12cm away from convex mirror of focal length 15...
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A 4.5 cm needle placed 12cm away from convex mirror of focal length 15...
Given :-

u = - 12 cm

f = + 15 cm

Solution :-

Using lens formula,

1/f = 1/u + 1/v

⇒ 1/v = 1/f - 1/u

⇒ 1/v = 1/15 - 1/- 12

⇒ 1/v = 60/9

⇒ v = 6.7 cm

Magnification, m = - (- v/u) = h₂/h₁

⇒ m = - 6.7/- 12

⇒ m = 0.558

m = h₂/h₁

h₂ = h₁ × m

⇒ h₂ = 0.558 × 4.5

⇒ h₂ = 2.5 cm.

As the needle is moved further from the mirror, image moves to the focus and the size of image goes on decreasing.
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A 4.5 cm needle placed 12cm away from convex mirror of focal length 15cm. Give the location of image and magnification. Describe what happens to the image as the needle is moved farther from the mirror.?
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A 4.5 cm needle placed 12cm away from convex mirror of focal length 15cm. Give the location of image and magnification. Describe what happens to the image as the needle is moved farther from the mirror.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A 4.5 cm needle placed 12cm away from convex mirror of focal length 15cm. Give the location of image and magnification. Describe what happens to the image as the needle is moved farther from the mirror.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4.5 cm needle placed 12cm away from convex mirror of focal length 15cm. Give the location of image and magnification. Describe what happens to the image as the needle is moved farther from the mirror.?.
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