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The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is ?
    Correct answer is '0'. Can you explain this answer?
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    The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)...
    In Cr(CO)6, the central Cr atom is d2sp3 hybridised. Hence all the electrons in its valence shell is paired. So it has net magnetic moment zero (0 BM).
    The electron configuration is [Ar]3d54s1.We have to accomodate the 6 Ligands and the fact that CO is a strong ligand.
    This results in d2sp3 hybridization. Therefore, there are no unpaired electrons in Cr(CO)6. Hence n=0
    And the spin only magnetic moment is also 0.
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    The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is ?Correct answer is '0'. Can you explain this answer?
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