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In the Freidel Craft's acylation reaction, the effective electrophile is
  • a)
    RCOCl+
  • b)
    AlCl3
  • c)
    RCOCl
  • d)
    RCO+
Correct answer is option 'D'. Can you explain this answer?
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In the Freidel Crafts acylation reaction, the effective electrophile i...
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In the Freidel Crafts acylation reaction, the effective electrophile i...
Explanation:

  • The Friedel-Crafts acylation reaction involves the acylation of aromatic compounds by the use of acyl halides or anhydrides in the presence of a Lewis acid catalyst such as AlCl3.

  • The reaction mechanism involves the formation of an intermediate complex between the Lewis acid catalyst and the acyl halide which activates it for reaction with the benzene ring.

  • The activated acyl halide acts as an electrophile and attacks the benzene ring to form an intermediate which upon protonation yields the final product.

  • However, the effective electrophile in the reaction is not the acyl halide or the Lewis acid catalyst but the acylium ion (RCO+).

  • This intermediate is formed by the reaction of the acyl halide with the Lewis acid catalyst and is the actual electrophile that reacts with the benzene ring.

  • The acylium ion is stabilized by resonance and is a much stronger electrophile than the acyl halide.

  • Thus, the effective electrophile in the Friedel-Crafts acylation reaction is the acylium ion (RCO+).

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In the Freidel Crafts acylation reaction, the effective electrophile isa)RCOCl+b)AlCl3c)RCOCld)RCO+Correct answer is option 'D'. Can you explain this answer?
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