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Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit is
- a)25%
- b)50%
- c)70%
- d)90%
Correct answer is option 'B'. Can you explain this answer?
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Compound A is extracted from a solution of A + B into a pure solvent S...
The maximum percentage extraction achieved in the unit is
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Compound A is extracted from a solution of A + B into a pure solvent S...
Problem:
Compound A is extracted from a solution of A and B into a pure solvent S using a co-current liquid-liquid extraction unit. The inlet rate of the solution containing A is 200 moles of B/hr.m^2 and the solvent flow rate is 400 moles of S/m^2.hr. The equilibrium data is represented by Y = 3X^2, where Y is the moles of A/moles of B and X is the moles of A/moles of S. Calculate the maximum percentage extraction achieved in the unit.
Solution:
To find the maximum percentage extraction achieved in the unit, we need to determine the point of maximum extraction on the equilibrium curve.
Equilibrium Data:
The equilibrium data is given by Y = 3X^2, where Y is the moles of A/moles of B and X is the moles of A/moles of S.
Understanding the Co-current Liquid-Liquid Extraction:
In a co-current liquid-liquid extraction, the feed containing solute A and solvent B is introduced at the top of the extraction column, while the pure solvent S is introduced at the bottom of the column. The solute A is extracted from the feed into the solvent S as they flow in the same direction. The extraction process is based on the difference in solubility and distribution of the solute between the two immiscible liquid phases.
Calculation:
1. Solute flow rate:
The solute flow rate can be calculated using the inlet rate of the solution containing A and the equilibrium data:
Solute flow rate = Inlet rate of solution containing A * (1 - Y)
= 200 * (1 - 3X^2)
2. Solvent flow rate:
The solvent flow rate is given as 400 moles of S/m^2.hr.
3. Mass balance:
For a co-current extraction unit, the mass balance equation is given by:
Solute flow rate = Solvent flow rate * Y
Substituting the values, we get:
200 * (1 - 3X^2) = 400 * Y
Simplifying the equation, we get:
1 - 3X^2 = 2Y
X^2 = (1 - 2Y)/3
4. Maximum extraction:
To find the point of maximum extraction, we differentiate X^2 with respect to Y and equate it to zero:
d(X^2)/dY = (2 - 2Y)/3 = 0
Solving the equation, we get:
Y = 1/2
5. Maximum percentage extraction:
The percentage extraction is given by:
Percentage extraction = (Y * 100) / Inlet rate of solution containing A
= (1/2 * 100) / 200
= 50%
Therefore, the maximum percentage extraction achieved in the unit is 50%. The correct answer is option B.
Compound A is extracted from a solution of A and B into a pure solvent S using a co-current liquid-liquid extraction unit. The inlet rate of the solution containing A is 200 moles of B/hr.m^2 and the solvent flow rate is 400 moles of S/m^2.hr. The equilibrium data is represented by Y = 3X^2, where Y is the moles of A/moles of B and X is the moles of A/moles of S. Calculate the maximum percentage extraction achieved in the unit.
Solution:
To find the maximum percentage extraction achieved in the unit, we need to determine the point of maximum extraction on the equilibrium curve.
Equilibrium Data:
The equilibrium data is given by Y = 3X^2, where Y is the moles of A/moles of B and X is the moles of A/moles of S.
Understanding the Co-current Liquid-Liquid Extraction:
In a co-current liquid-liquid extraction, the feed containing solute A and solvent B is introduced at the top of the extraction column, while the pure solvent S is introduced at the bottom of the column. The solute A is extracted from the feed into the solvent S as they flow in the same direction. The extraction process is based on the difference in solubility and distribution of the solute between the two immiscible liquid phases.
Calculation:
1. Solute flow rate:
The solute flow rate can be calculated using the inlet rate of the solution containing A and the equilibrium data:
Solute flow rate = Inlet rate of solution containing A * (1 - Y)
= 200 * (1 - 3X^2)
2. Solvent flow rate:
The solvent flow rate is given as 400 moles of S/m^2.hr.
3. Mass balance:
For a co-current extraction unit, the mass balance equation is given by:
Solute flow rate = Solvent flow rate * Y
Substituting the values, we get:
200 * (1 - 3X^2) = 400 * Y
Simplifying the equation, we get:
1 - 3X^2 = 2Y
X^2 = (1 - 2Y)/3
4. Maximum extraction:
To find the point of maximum extraction, we differentiate X^2 with respect to Y and equate it to zero:
d(X^2)/dY = (2 - 2Y)/3 = 0
Solving the equation, we get:
Y = 1/2
5. Maximum percentage extraction:
The percentage extraction is given by:
Percentage extraction = (Y * 100) / Inlet rate of solution containing A
= (1/2 * 100) / 200
= 50%
Therefore, the maximum percentage extraction achieved in the unit is 50%. The correct answer is option B.
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Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer?
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Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer?.
Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer?.
Solutions for Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m2 and the solvent flow, rate is 400 moles of S/m2. hr. The equilibrium data is represented by Y = 3X2 , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit isa)25%b)50%c)70%d)90%Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemical Engineering.
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