A man is carrying the heavy luggage from one platform to the other of ...
(b) The force is acting perpendicular to the direction of displacement of luggage
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A man is carrying the heavy luggage from one platform to the other of ...
Actually there is nothing going to be happening with the luggage. Because it is stationary. only the passenger is moving .
A man is carrying the heavy luggage from one platform to the other of ...
The Reason for the Correct Answer
The correct reason for the work done being zero in this scenario is that the force is acting perpendicular to the direction of displacement of the luggage. Let's explore this in more detail.
Understanding Work Done
To understand why the work done is zero in this situation, we need to understand the concept of work done in physics. Work done is defined as the product of the force applied on an object and the displacement of the object in the direction of the force. Mathematically, it is expressed as:
Work Done (W) = Force (F) * Displacement (d) * cos θ
Here, θ represents the angle between the force and the displacement vectors. If the force and displacement are in the same direction (θ = 0°), the work done will be maximum. If they are perpendicular to each other (θ = 90°), the work done will be zero.
Analysis of the Given Scenario
In the given scenario, the man is carrying the heavy luggage from one platform to the other of a railway station. Since the luggage is being carried horizontally, the displacement is in a horizontal direction. Let's consider the force exerted by the man on the luggage.
Force Acting on the Luggage
When the man carries the luggage, he exerts an upward force on the luggage to counteract the force of gravity pulling it downwards. This upward force is equal in magnitude and opposite in direction to the force of gravity acting on the luggage.
Direction of Force and Displacement
In this scenario, the force exerted by the man is acting vertically upwards, while the displacement of the luggage is in the horizontal direction (from one platform to the other). The force and displacement vectors are perpendicular to each other, making the angle θ = 90°.
Calculation of Work Done
Using the formula for work done, we can see that cos 90° = 0. Therefore, the work done is:
Work Done (W) = Force (F) * Displacement (d) * cos θ
= F * d * 0
= 0
Conclusion
Hence, the reason the work done is zero in this scenario is because the force exerted by the man on the luggage is acting perpendicular to the direction of displacement. This means that the force is not contributing to the movement of the luggage in the horizontal direction, resulting in zero work done.
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