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If x is ones digit and y is tens digit of a two digit number, then the cube of the number will be _________.
- a)(10y + x)3
- b)(10y + x)2
- c)(10x + y)3
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If x is ones digit and y is tens digit of a two digit number, then the...
Solution:
Let the two digit number be xy.
Then, the number can be represented as 10y + x.
Using the formula for the cube of a binomial, we have:
(10y + x)^3 = (10y)^3 + 3(10y)^2(x) + 3(10y)(x^2) + x^3
= 1000y^3 + 300x(y^2) + 30(x^2)(y) + x^3
= 1000y^3 + 300xy(y) + 30x^2(y) + x^3
= (1000y^3 + 300xy(y) + 30x^2(y) + x^3)
= (10y x)^3
Therefore, the cube of the two digit number xy is (10y x)^3.
Hence, the correct option is A.
Let the two digit number be xy.
Then, the number can be represented as 10y + x.
Using the formula for the cube of a binomial, we have:
(10y + x)^3 = (10y)^3 + 3(10y)^2(x) + 3(10y)(x^2) + x^3
= 1000y^3 + 300x(y^2) + 30(x^2)(y) + x^3
= 1000y^3 + 300xy(y) + 30x^2(y) + x^3
= (1000y^3 + 300xy(y) + 30x^2(y) + x^3)
= (10y x)^3
Therefore, the cube of the two digit number xy is (10y x)^3.
Hence, the correct option is A.
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Community Answer
If x is ones digit and y is tens digit of a two digit number, then the...
Absolutely option A is correct answer because , y is the place of tenth digit so the number of y digit is 10y and x is the place of ones digit . so the number we found that ( 10y+ x) . and cube of the number is (10 y+ x) 3 .
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