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Diameter of human eye lens is 2 mm. What will be the minimum distance between two points to resolve them, which are situated at a distance of 50 m from eye? (The wavelength of light is 500 Å)
  • a)
    2.32 m
  • b)
    4.28 mm
  • c)
    1.25 cm
  • d)
    12.48 cm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Diameter of human eye lens is 2 mm. What will be the minimum distance ...
Angular limit of resolution of eye = wavelength of light/diameter of eye lens
∵ θ = λ/d ...(i)
if, Y is the minimum resolution between two object at distance from eyes, then
θ = Y/D ...(ii)
From eqs (i) and (ii), we have

y = λD/d ...(iii)
Given,λ = 5000Å = 5 x 10-7m, D = 50m
and d = 2mm = 2 x 10-3 m
on substituting eq (i) and eq (ii) 2 in eq (iii) then, we get

= 12.5 x 10-3m = 1.25 m
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Most Upvoted Answer
Diameter of human eye lens is 2 mm. What will be the minimum distance ...
Nm)

We can use the Rayleigh criterion to determine the minimum distance between two points that can be resolved by the human eye:

θ = 1.22 λ / D

where θ is the angular resolution, λ is the wavelength of light, and D is the diameter of the lens.

First, we need to convert the distance of 50 m into an angle:

θ = tan⁻¹ (d / D)

where d is the distance between the two points and D is the distance from the eye to the object (in this case, 50 m). Since we want to find the minimum distance between two points that can be resolved, we can set d equal to this distance.

θ = tan⁻¹ (2 / 50000) = 0.004 degrees

Now we can use the Rayleigh criterion to find the minimum diameter of the two points that can be resolved at this angle:

D = 1.22 λ / θ = 1.22 * 500 * 10⁻⁹ / (0.004 * π/180) = 57.9 μm

Therefore, the minimum distance between two points that can be resolved by the human eye at a distance of 50 m is 57.9 μm.
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