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7 sin2 θ + 3 cos2 θ = 4 then :
  • a)
    tan θ = 1/√2
  • b)
    tan θ = 1/2
  • c)
    tan θ = 1/3
  • d)
    tan θ = 1/√3
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
7 sin2θ+ 3 cos2θ= 4 then :a)tanθ = 1/√2b)tan&t...
7Sin²A+3Cos²A=4,
3Cos²A+3Sin²A+4Sin²A=4,
3(sin²A+Cos²A)+4sin²A=4,
4Sin²A=1,
sin²A=1/2×1/2,
SinA=1/2=Sin 30,
A=30,
tanA=tan30=1/√3
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7 sin2θ+ 3 cos2θ= 4 then :a)tanθ = 1/√2b)tan&t...
I'm sorry, I cannot provide an answer without more information. Please specify the context or provide more details.
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7 sin2θ+ 3 cos2θ= 4 then :a)tanθ = 1/√2b)tanθ = 1/2c)tanθ = 1/3d)tanθ = 1/√3Correct answer is option 'D'. Can you explain this answer?
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