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Two years ago a father was the five time as old as his son 2 years later his age will be 8 years more than three times the age of the Son . find the present is is of father and son?
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Given Information:
- Two years ago, the father was five times as old as his son.
- Two years later, the father's age will be 8 years more than three times the age of the son.

Let's solve the problem step by step:

Step 1: Assign Variables
Let the present age of the son be S years.
Let the present age of the father be F years.

Step 2: Translate the Given Information into Equations
From the first statement, we have:
F - 2 = 5(S - 2) (Father was five times as old as his son two years ago)
From the second statement, we have:
F + 2 = 3(S + 2) + 8 (Father's age 2 years later will be 8 more than three times the age of the son)

Step 3: Solve the Equations
Now, we will solve the two equations simultaneously to find the present ages of the father and the son.
1. F - 2 = 5S - 10 (Expanding the first equation)
F = 5S - 8
2. F + 2 = 3S + 6 + 8 (Expanding the second equation)
F = 3S + 14
Now, equating both expressions for F:
5S - 8 = 3S + 14
2S = 22
S = 11

Step 4: Find the Present Ages
Substitute the value of S back into the first equation to find the father's present age:
F = 5(11) - 8
F = 55 - 8
F = 47

Conclusion:
The present age of the son is 11 years, and the present age of the father is 47 years.
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