Calculation of Required Amount of Bromine to Convert Phenol into 2,4,6-TribromophenolGiven: - Amount of phenol = 2 g- Target product = 2,4,6-tribromophenolStep 1: Write the Balanced Chemical EquationThe reaction between phenol and bromine to form 2,4,6-tribromophenol can be represented by the following balanced chemical equation:C6H5OH + 3Br2 → C6H2Br3OH + 3HBrStep 2: Calculate the Molecular Weight of Phenol and 2,4,6-Tribromophenol- Molecular weight of phenol (C6H5OH) = 94.11 g/mol- Molecular weight of 2,4,6-tribromophenol (C6H2Br3OH) = 329.76 g/molStep 3: Calculate the Number of Moles of PhenolNumber of moles of phenol = Mass of phenol / Molecular weight of phenol= 2 g / 94.11 g/mol= 0.0212 molStep 4: Calculate the Number of Moles of 2,4,6-TribromophenolSince the reaction is 1:1 between phenol and 2,4,6-tribromophenol, the number of moles of 2,4,6-tribromophenol produced will be equal to the number of moles of phenol used.Number of moles of 2,4,6-tribromophenol = Number of moles of phenol= 0.0212 molStep 5: Calculate the Required Amount of BromineFrom the balanced chemical equation, we can see that three moles of bromine are required to produce one mole of 2,4,6-tribromophenol.Number of moles of bromine required = 3 x Number of moles of 2,4,6-tribromophenol= 3 x 0.0212 mol= 0.0637 molStep 6: Calculate the Mass of Bromine RequiredMass of bromine required = Number of moles of bromine x Molecular weight of bromine= 0.0637 mol x 159.81 g/mol= 10.22 gTherefore, the amount of bromine required to convert 2 g of phenol into 2,4,6-tribromophenol is 10.22 g, which is option (c).