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A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help?
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A body of mass 4 kg is accelerated upon by a constant force, travels a...
Given:
- Mass of the body (m) = 4 kg
- Distance traveled in the first second (s1) = 5 m
- Distance traveled in the third second (s3) = 3 m
To find:
- Force acting on the body
Formula:
- The distance traveled by a body under constant acceleration can be calculated using the equation: s = ut + (1/2)at^2
- Where s is the distance, u is the initial velocity, t is the time, and a is the acceleration.
- The acceleration can be calculated using the equation: a = (v - u)/t
- Where v is the final velocity and u is the initial velocity.
Calculations:
Acceleration in the first second:
- Using the equation s = ut + (1/2)at^2, we can write:
5 = 0 + (1/2)a(1^2)
- Simplifying the equation:
5 = (1/2)a
- Multiplying both sides of the equation by 2:
10 = a
Acceleration in the third second:
- Using the equation s = ut + (1/2)at^2, we can write:
3 = 0 + (1/2)a(3^2)
- Simplifying the equation:
3 = (9/2)a
- Multiplying both sides of the equation by 2/9:
(2/9) * 3 = a
2/3 = a
Calculating the force:
- We know that force (F) = mass (m) * acceleration (a)
- Substituting the values of mass and acceleration:
F = 4 * 10 = 40 N (in the first second)
F = 4 * (2/3) = 8/3 N (in the third second)
Answer:
- The force acting on the body in the first second is 40 N.
- The force acting on the body in the third second is 8/3 N.
- Mass of the body (m) = 4 kg
- Distance traveled in the first second (s1) = 5 m
- Distance traveled in the third second (s3) = 3 m
To find:
- Force acting on the body
Formula:
- The distance traveled by a body under constant acceleration can be calculated using the equation: s = ut + (1/2)at^2
- Where s is the distance, u is the initial velocity, t is the time, and a is the acceleration.
- The acceleration can be calculated using the equation: a = (v - u)/t
- Where v is the final velocity and u is the initial velocity.
Calculations:
Acceleration in the first second:
- Using the equation s = ut + (1/2)at^2, we can write:
5 = 0 + (1/2)a(1^2)
- Simplifying the equation:
5 = (1/2)a
- Multiplying both sides of the equation by 2:
10 = a
Acceleration in the third second:
- Using the equation s = ut + (1/2)at^2, we can write:
3 = 0 + (1/2)a(3^2)
- Simplifying the equation:
3 = (9/2)a
- Multiplying both sides of the equation by 2/9:
(2/9) * 3 = a
2/3 = a
Calculating the force:
- We know that force (F) = mass (m) * acceleration (a)
- Substituting the values of mass and acceleration:
F = 4 * 10 = 40 N (in the first second)
F = 4 * (2/3) = 8/3 N (in the third second)
Answer:
- The force acting on the body in the first second is 40 N.
- The force acting on the body in the third second is 8/3 N.
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A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help?
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A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help?.
A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 4 kg is accelerated upon by a constant force, travels a distance of 5m in the first second and the distance of 3 m in the third second. The force acting on the body is? Please help?.
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