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A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct?
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A body of mass 4kg is accelerated upon by a constant force,travels a d...
Understanding the Problem
To find the force acting on a body of mass 4 kg, we need to analyze the distances covered in different time intervals. The body travels 5m in the first second and 2m in the third second.
Distance Covered in Time Intervals
- Distance in 1st second (s1): 5m
- Distance in 3rd second (s3): 2m
Using the equations of motion, we can derive the acceleration and subsequently the force.
Equation for Distance Covered
The distance covered in the nth second is given by:
s_n = u + 0.5a(2n-1)
Where:
- s_n: distance in nth second
- u: initial velocity (which is 0 for this case)
- a: acceleration
Calculating Distances
1. For 1st second (n=1):
- s1 = 0 + 0.5a(2*1-1) = 0.5a
- Setting s1 = 5m:
- 0.5a = 5
- a = 10 m/s²
2. For 3rd second (n=3):
- s3 = 0 + 0.5a(2*3-1) = 0.5a*5
- Setting s3 = 2m:
- 0.5a*5 = 2
- a = 0.8 m/s²
Finding the Force
Using Newton's second law (F = ma):
- F = 4kg * 0.8 m/s² = 3.2N
Conclusion
The calculated force of 3.2N is not among the options provided, and option D (4N) is incorrect. The correct approach indicates that the force should be around 3.2N, which suggests an error in the original assumptions or calculations. Therefore, the force acting on the body cannot be conclusively stated as 4N based on the provided data.
To find the force acting on a body of mass 4 kg, we need to analyze the distances covered in different time intervals. The body travels 5m in the first second and 2m in the third second.
Distance Covered in Time Intervals
- Distance in 1st second (s1): 5m
- Distance in 3rd second (s3): 2m
Using the equations of motion, we can derive the acceleration and subsequently the force.
Equation for Distance Covered
The distance covered in the nth second is given by:
s_n = u + 0.5a(2n-1)
Where:
- s_n: distance in nth second
- u: initial velocity (which is 0 for this case)
- a: acceleration
Calculating Distances
1. For 1st second (n=1):
- s1 = 0 + 0.5a(2*1-1) = 0.5a
- Setting s1 = 5m:
- 0.5a = 5
- a = 10 m/s²
2. For 3rd second (n=3):
- s3 = 0 + 0.5a(2*3-1) = 0.5a*5
- Setting s3 = 2m:
- 0.5a*5 = 2
- a = 0.8 m/s²
Finding the Force
Using Newton's second law (F = ma):
- F = 4kg * 0.8 m/s² = 3.2N
Conclusion
The calculated force of 3.2N is not among the options provided, and option D (4N) is incorrect. The correct approach indicates that the force should be around 3.2N, which suggests an error in the original assumptions or calculations. Therefore, the force acting on the body cannot be conclusively stated as 4N based on the provided data.
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A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct?
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A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct?.
A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 4kg is accelerated upon by a constant force,travels a distance of 5m in the first second and a distance of 2m in the third second.The force acting on the body is A)6N B)8N C)2N D)4N Option D is correct?.
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