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Two slits in YDSE are placed 2 mm from each other. Interference pattern is observed on a screen placed 2m from the plane of slits what is the fringe width for a light of wavelength 400nm?
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Two slits in YDSE are placed 2 mm from each other. Interference patter...
Calculation of Fringe Width in YDSE


Given Data:


  • Distance between the slits, d = 2 mm = 0.002 m

  • Distance of the screen from the plane of slits, D = 2 m

  • Wavelength of light, λ = 400 nm = 4 x 10^-7 m



Formula:

Fringe width, w = λD/d

Calculation:

Substituting the given values in the formula, we get:
w = (4 x 10^-7 m) x (2 m) / (0.002 m) = 0.4 mm

Explanation:

In Young's Double Slit Experiment, when a beam of light is passed through two narrow slits, it diffracts and forms an interference pattern on a screen placed at a distance D from the plane of slits. The pattern consists of alternate bright and dark fringes, known as interference fringes. The fringe width is the distance between two adjacent bright or dark fringes. It is given by the formula w = λD/d, where λ is the wavelength of light, D is the distance of the screen from the plane of slits, and d is the distance between the slits. In this case, the fringe width is found to be 0.4 mm for a light of wavelength 400 nm.
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Two slits in YDSE are placed 2 mm from each other. Interference patter...
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Two slits in YDSE are placed 2 mm from each other. Interference pattern is observed on a screen placed 2m from the plane of slits what is the fringe width for a light of wavelength 400nm?
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