Write a balanced chemical equation for the following reaction. Ethanol is warmed with ethanoic acid to form ethly acetate in the presence of conc.H2SO4 ?

Question

Answer

Ethanol is warmed with ethanoic acid in the presence of a few drops of concentrated sulphuric acid a sweet smelling Ester called ethyl ethanoate is formed.

CH3COOH + C2H5OH ----Conc.H2SO4→ CH3COOH + H2O
This reaction to form an ester is called esterification. This reaction is also used as a test for ethanoic acid.

Answer

Answer

Balanced Chemical Equation
C2H5OH + CH3COOH → C4H8O2 + H2O

Explanation

The reaction between ethanol and ethanoic acid to form ethyl acetate in the presence of concentrated sulfuric acid is an esterification reaction. Esterification is a chemical reaction between an alcohol and a carboxylic acid, which results in the formation of an ester and water. In this reaction, ethanol and ethanoic acid react to form ethyl acetate and water. The reaction is catalyzed by concentrated sulfuric acid, which acts as a dehydrating agent, removing water from the reaction mixture and driving the reaction forward.

The Role of Concentrated Sulfuric Acid

Concentrated sulfuric acid is used as a catalyst in this reaction. It acts as a dehydrating agent, which means that it removes water from the reaction mixture. The removal of water from the reaction mixture drives the equilibrium of the reaction towards the formation of the ester. Sulfuric acid also serves to protonate the carboxylic acid, which makes it more reactive towards the alcohol.

Conclusion

In conclusion, the reaction between ethanol and ethanoic acid to form ethyl acetate in the presence of concentrated sulfuric acid is an esterification reaction. The balanced chemical equation for the reaction is C2H5OH + CH3COOH → C4H8O2 + H2O. The role of concentrated sulfuric acid is to act as a dehydrating agent and protonate the carboxylic acid, making it more reactive towards the alcohol.

Answer

When an acid is treated with an alcohol in presence of a catalyst(conc. H2SO4) an ester is formed with the elimination of water molecule, this is called esterification reaction.

When ethanoic acid is treated with ethanol in presence of dehydrating agent like conc. H2SO4 ethyl ethanoate is formed.

C2H5COOH + C2H5OH → C2H5COOC2H5 + H2O

Answer

(All are in aqueous state)

The ester formed has a fruity smell which is it's identification test.

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