A train 200 metres long is moving at the rate of 40 kmph. In how many ...
The correct answer is D as
time = Length of train / speed of train
time = 0.20 km / 40 km/h
time = (0.20 / 40) h
time = 5×10⁻³ h and to convert it to seconds just multiply it by 3600 s/h
time = 5×10⁻³ h * 3600 s/h the unit h is cancelled and the unit seconds remain
time = 18 seconds
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A train 200 metres long is moving at the rate of 40 kmph. In how many ...
Understanding the Problem
To determine how long it takes for a train to cross a stationary man, we need to consider the length of the train and its speed.
Given Data
- Length of the train: 200 meters
- Speed of the train: 40 km/h
Conversion of Speed
First, we need to convert the speed from kilometers per hour to meters per second for easier calculations.
- The formula to convert km/h to m/s is:
Speed (m/s) = Speed (km/h) × (1000 m / 1 km) × (1 hour / 3600 seconds)
Calculating this gives:
- Speed = 40 × (1000 / 3600) = 40 × (5/18) = 11.11 m/s (approximately)
Time Calculation
Now we can calculate the time taken to cross the man:
- Time = Distance / Speed
- Here, the distance is the length of the train, which is 200 meters.
So, we compute:
- Time = 200 m / 11.11 m/s ≈ 18 seconds
Conclusion
Therefore, it takes approximately 18 seconds for the train to completely cross the man standing by the railway line.
The correct answer is option 'D'.
A train 200 metres long is moving at the rate of 40 kmph. In how many ...
The correct answer is D as
time = Length of train / speed of train
time = 0.20 km / 40 km/h
time = (0.20 / 40) h
time = 5×10⁻³ h and to convert it to seconds just multiply it by 3600 s/h
time = 5×10⁻³ h * 3600 s/h the unit h is cancelled and the unit seconds remain
time = 18 seconds