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If x=p,y=q is a solution of the equations x 2y 1=0 and 2x-3y-12=0,then the values of p and q are respectively?
Most Upvoted Answer
If x=p,y=q is a solution of the equations x 2y 1=0 and 2x-3y-12=0,then...
Solution:

Given equations are:

x^2y+1=0 ...(1)

2x-3y-12=0 ...(2)

Substituting x=p and y=q in equations (1) and (2), we get:

p^2q+1=0 ...(3)

2p-3q-12=0 ...(4)

Finding the value of p:

From equation (3), we get:

p^2q=-1

p^2=(-1)/q

p=±√(-1/q)

Since p is a real number, q cannot be negative. Hence, q>0.

So, p=±i/√q

But we know that p is a real number.

Therefore, p=0

Finding the value of q:

From equation (4), we get:

2p-3q-12=0

Substituting p=0, we get:

-3q-12=0

q=-4

Therefore, the values of p and q are 0 and -4 respectively.
Community Answer
If x=p,y=q is a solution of the equations x 2y 1=0 and 2x-3y-12=0,then...
Lack of symbols in equation 1...
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If x=p,y=q is a solution of the equations x 2y 1=0 and 2x-3y-12=0,then the values of p and q are respectively?
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