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Find the position of an object which when placed in front of a concave mirror of focal length 20cm produces a virtual image which is thrice the size of object?
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Problem:
Find the position of an object which when placed in front of a concave mirror of focal length 20cm produces a virtual image which is thrice the size of object?

Solution:

Step 1: Identify the given values and formula to be used.

Given:
f = -20cm (focal length of concave mirror)
m = -3 (magnification)

Formula:
m = -v/u (where m is magnification, v is the image distance, and u is the object distance)

Step 2: Substitute the values in the formula.

m = -v/u
-3 = -v/u

Step 3: Solve for v.

-3u = v

Step 4: Use the mirror formula to find u.

The mirror formula is given by:
1/f = 1/v + 1/u

Substituting the given values, we get:

1/-20 = 1/-3u + 1/u

Solving for u, we get:

u = -30 cm

Step 5: Use the magnification formula to find v.

m = -v/u
-3 = -v/-30

v = -90 cm

Step 6: Interpret the solution.

The object must be placed at a distance of 30 cm from the concave mirror to produce a virtual image which is three times the size of the object. The image will be formed at a distance of 90 cm from the mirror.

Final Answer: The object must be placed at a distance of 30 cm from the concave mirror to produce a virtual image which is three times the size of the object.
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Find the position of an object which when placed in front of a concave mirror of focal length 20cm produces a virtual image which is thrice the size of object?
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