Calculation of ATP formed from 10 molecules of fructose-1,6-bisphosphate in aerobic respiration

Glycolysis is the first stage of aerobic respiration that occurs in the cytoplasm of the cell. It involves the breakdown of glucose or other sugars into pyruvate, which is further oxidized to form ATP. The net gain of ATP in glycolysis is 2 ATP molecules per glucose molecule.

The breakdown of fructose-1,6-bisphosphate (a 6-carbon sugar) in glycolysis involves multiple enzymatic reactions, which yield 2 ATP molecules per fructose-1,6-bisphosphate molecule. Therefore, the total ATP formed from 10 molecules of fructose-1,6-bisphosphate in glycolysis can be calculated as follows:

ATP formed per molecule of fructose-1,6-bisphosphate = 2 ATP
ATP formed from 10 molecules of fructose-1,6-bisphosphate = (2 ATP/molecule) x (10 molecules) = 20 ATP

However, the pyruvate formed from glycolysis undergoes further oxidative metabolism in the mitochondria, which yields a much higher amount of ATP. The complete oxidation of glucose yields a total of 36-38 ATP molecules per glucose molecule, depending on the efficiency of the electron transport chain. Therefore, the total ATP yield from 10 molecules of fructose-1,6-bisphosphate in aerobic respiration would be much higher than 20 ATP.

Yaa....as this fructose -1,6 bisphosphate cannot enter directly in glycolysis ...it should convert into glucose which yields 2 atp...then after it enters..glycolysis and Krebs cycle which yields 38 atp...so totally 40 atp...
as they r asking for 10 molecules .. of fructose 1,6 bisphosphate...(.10×40=400..)... so option 4 is correct ans...hope it's help u...