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Solve for x and y : (2/x-1) (y-2)/4)=2, (3/2(x-1)) (2(y-2/5)=47/20?
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Solve for x and y : (2/x-1) (y-2)/4)=2, (3/2(x-1)) (2(y-2/5)=47/20?
Mention appropriate signs between ( 2 / x -1 ) & ( y - 2 / 4 )  , and also between { 3 / 2 ( x - 1 ) } , { 2 ( y  - 2 / 5 ) } . 
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Solve for x and y : (2/x-1) (y-2)/4)=2, (3/2(x-1)) (2(y-2/5)=47/20?
Solution:

Given equations are

(2/x-1) (y-2)/4) = 2 ----(1)

(3/2(x-1)) (2(y-2/5))=47/20 ----(2)

Simplifying Equation 1:

(2/x-1) (y-2)/4) = 2

Multiplying both sides by (x-1) (to get rid of the denominator in the first term)

2(y-2)/(x-1) = 8

y-2 = 4(x-1)

y = 4x - 2

Substituting this value of y in Equation 2

(3/2(x-1)) (2(y-2/5))=47/20

(3/2(x-1)) (2(4x-2-2/5))=47/20

Simplifying Equation 2:

(3/2(x-1)) (2(y-2/5))=47/20

(3/2(x-1)) (2(y-2/5))=47/20

(3/2(x-1)) (2(4x-2-2/5))=47/20

(3/2(x-1)) (8x-9/5)=47/20

Multiplying both sides by 10 (to get rid of the denominator)

6(8x-9/5)=47

48x - 54/5 = 47/6

48x = 47/6 + 54/5

48x = 1579/30

x = 1579/30 * 1/48

x = 329/240

Substituting this value of x in Equation 1

(2/x-1) (y-2)/4) = 2

(2/(329/240 -1)) (y-2)/4) = 2

(2/(240-329/240)) (y-2)/4) = 2

(2/(240-329/240)) (y-2)/4) = 2

(2/(240 * 240/240 - 329/240)) (y-2)/4) = 2

(2/(57600/240 - 329/240)) (y-2)/4) = 2

(2/(57371/240)) (y-2)/4) = 2

Multiplying both sides by 57371/240 (to get rid of the denominator in the first term)

y-2 = 57371/60

y = 57371/60 + 2

y = 2879/15

Therefore the values of x and y are x = 329/240 and y = 2879/15.
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