Solubility of AgCl is least in A)0.1M AlCl3 B)pure water C)0.1M BaCl2 ...
Solution:
To determine the solubility of AgCl in different solutions, we need to consider the common ion effect and the concept of solubility product constant (Ksp).
The solubility product constant (Ksp) is an equilibrium constant that represents the equilibrium between a solid compound and its dissolved ions in a solution. For AgCl, the solubility product constant is given by the equation:
AgCl(s) ⇌ Ag+(aq) + Cl-(aq)
Ksp = [Ag+][Cl-]
The solubility of AgCl is determined by the concentration of Ag+ and Cl- ions in the solution. When a common ion is present in the solution, it reduces the solubility of the compound due to Le Chatelier's principle.
Let's analyze the solubility of AgCl in each given solution:
A) 0.1M AlCl3:
AlCl3 dissociates into Al3+ and Cl- ions. The Cl- ions from AlCl3 will increase the concentration of Cl- ions in the solution. Therefore, the solubility of AgCl will be decreased due to the common ion effect.
B) Pure water:
Pure water does not contain any common ions. Therefore, the solubility of AgCl will not be affected by the presence of any common ions.
C) 0.1M BaCl2:
BaCl2 dissociates into Ba2+ and Cl- ions. The Cl- ions from BaCl2 will increase the concentration of Cl- ions in the solution. Therefore, the solubility of AgCl will be decreased due to the common ion effect.
D) 0.1M NaCl:
NaCl dissociates into Na+ and Cl- ions. The Cl- ions from NaCl will increase the concentration of Cl- ions in the solution. Therefore, the solubility of AgCl will be decreased due to the common ion effect.
Therefore, the solubility of AgCl is least in option A) 0.1M AlCl3.
Solubility of AgCl is least in A)0.1M AlCl3 B)pure water C)0.1M BaCl2 ...
Op A , 0.1M AlCl3