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The conversion of d-form of an optically active compound into l-form of the same or of different compound or vice-versa is known as:
- a)Resolution
- b)Walden inversion
- c)Racemisation
- d)External compensation
Correct answer is option 'B'. Can you explain this answer?
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The conversion of d-form of an optically active compound into l-form o...
The conversion of d-form of an optically active compound into l-form of the same or of different compound or vice-versa is known as Walden inversion.
Walden inversion is a process where the configuration of an optically active compound is changed from d-form to l-form or vice versa. It involves the inversion of the configuration of the stereocenter in the molecule.
Explanation:
Walden inversion is named after the German chemist Paul Walden, who first described this phenomenon. It occurs when an optically active compound undergoes a reaction that results in the inversion of the configuration at a chiral center.
Chiral center:
A chiral center is an atom in a molecule that is bonded to four different groups. It gives rise to stereoisomers that are non-superimposable mirror images of each other.
Inversion of configuration:
In a Walden inversion, the configuration of the chiral center changes from d-form to l-form or vice versa. This means that the stereochemistry of the compound is reversed, resulting in the formation of a stereoisomer that is the mirror image of the starting compound.
Reaction mechanism:
Walden inversion can occur through various reaction mechanisms. One common mechanism is through the attack of a nucleophile on a chiral center, resulting in the formation of an intermediate. The intermediate then rearranges to give the inverted configuration.
Importance:
Walden inversion is an important concept in organic chemistry, especially in the study of stereochemistry and enantiomerism. It is used to explain the behavior of optically active compounds and their reactions.
Example:
One example of Walden inversion is the reaction of an alkyl halide with a nucleophile. For instance, the reaction of (R)-2-bromobutane with a strong nucleophile such as hydroxide ion (OH-) would result in the formation of (S)-2-butanol through Walden inversion.
In conclusion, Walden inversion is the process of converting the d-form of an optically active compound into the l-form or vice versa. It involves the inversion of the configuration at a chiral center and is an important concept in stereochemistry and organic chemistry as a whole.
Walden inversion is a process where the configuration of an optically active compound is changed from d-form to l-form or vice versa. It involves the inversion of the configuration of the stereocenter in the molecule.
Explanation:
Walden inversion is named after the German chemist Paul Walden, who first described this phenomenon. It occurs when an optically active compound undergoes a reaction that results in the inversion of the configuration at a chiral center.
Chiral center:
A chiral center is an atom in a molecule that is bonded to four different groups. It gives rise to stereoisomers that are non-superimposable mirror images of each other.
Inversion of configuration:
In a Walden inversion, the configuration of the chiral center changes from d-form to l-form or vice versa. This means that the stereochemistry of the compound is reversed, resulting in the formation of a stereoisomer that is the mirror image of the starting compound.
Reaction mechanism:
Walden inversion can occur through various reaction mechanisms. One common mechanism is through the attack of a nucleophile on a chiral center, resulting in the formation of an intermediate. The intermediate then rearranges to give the inverted configuration.
Importance:
Walden inversion is an important concept in organic chemistry, especially in the study of stereochemistry and enantiomerism. It is used to explain the behavior of optically active compounds and their reactions.
Example:
One example of Walden inversion is the reaction of an alkyl halide with a nucleophile. For instance, the reaction of (R)-2-bromobutane with a strong nucleophile such as hydroxide ion (OH-) would result in the formation of (S)-2-butanol through Walden inversion.
In conclusion, Walden inversion is the process of converting the d-form of an optically active compound into the l-form or vice versa. It involves the inversion of the configuration at a chiral center and is an important concept in stereochemistry and organic chemistry as a whole.
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The conversion of d-form of an optically active compound into l-form of the same or of different compound or vice-versa is known as:a) Resolution b) Walden inversion c) Racemisation d) External compensation Correct answer is option 'B'. Can you explain this answer?
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