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Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.?
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Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average em...
Initial current, I1=5.0A
Final current, I2=0A
Change in current, dl=I1−I2=5A
Time taken for the charge, t=0.1s
Average emf, e=200V
For self inductance(L) of the coil, we have the relation for average emf as:
e=Ldtdi
L=dtdie
=0.15=4H200
Hence the self inductance of the coil is 4H.
Final current, I2=0A
Change in current, dl=I1−I2=5A
Time taken for the charge, t=0.1s
Average emf, e=200V
For self inductance(L) of the coil, we have the relation for average emf as:
e=Ldtdi
L=dtdie
=0.15=4H200
Hence the self inductance of the coil is 4H.
Community Answer
Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average em...
Calculating Self-Inductance of the Circuit
To calculate the self-inductance of the circuit, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force (emf) in a closed circuit is directly proportional to the rate of change of magnetic flux through the circuit.
Given data:
- Initial current (I1) = 5.0A
- Final current (I2) = 0.0A
- Time taken (Δt) = 0.1s
- Average induced emf (𝜀) = 200V
Step 1: Calculating the change in current (ΔI)
The change in current can be calculated by subtracting the final current from the initial current:
ΔI = I2 - I1
= 0.0A - 5.0A
= -5.0A
Step 2: Calculating the rate of change of current (dI/dt)
The rate of change of current can be calculated by dividing the change in current by the time taken:
dI/dt = ΔI / Δt
= -5.0A / 0.1s
= -50A/s
Step 3: Calculating the self-inductance (L)
According to Faraday's law, the induced emf (𝜀) is given by the equation:
𝜀 = -L * (dI/dt)
Rearranging the equation, we can solve for the self-inductance (L):
L = -𝜀 / (dI/dt)
= -200V / (-50A/s)
= 4V/A
Conclusion:
The estimated self-inductance of the circuit is 4V/A.
To calculate the self-inductance of the circuit, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force (emf) in a closed circuit is directly proportional to the rate of change of magnetic flux through the circuit.
Given data:
- Initial current (I1) = 5.0A
- Final current (I2) = 0.0A
- Time taken (Δt) = 0.1s
- Average induced emf (𝜀) = 200V
Step 1: Calculating the change in current (ΔI)
The change in current can be calculated by subtracting the final current from the initial current:
ΔI = I2 - I1
= 0.0A - 5.0A
= -5.0A
Step 2: Calculating the rate of change of current (dI/dt)
The rate of change of current can be calculated by dividing the change in current by the time taken:
dI/dt = ΔI / Δt
= -5.0A / 0.1s
= -50A/s
Step 3: Calculating the self-inductance (L)
According to Faraday's law, the induced emf (𝜀) is given by the equation:
𝜀 = -L * (dI/dt)
Rearranging the equation, we can solve for the self-inductance (L):
L = -𝜀 / (dI/dt)
= -200V / (-50A/s)
= 4V/A
Conclusion:
The estimated self-inductance of the circuit is 4V/A.
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Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.?
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Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.?.
Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Current in a circuit falls from 5.0A to 0.0A in 0.1s. if an average emf of 200V induced, give an estimate of the self - inductance of the circuit.?.
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