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Evaluate Sec 90-theta cosec-tan 90-theta cos^2 35 cos^2 55/tan 5 tan 15 tan 45 tan 75 tan 85?
Most Upvoted Answer
Evaluate Sec 90-theta cosec-tan 90-theta cos^2 35 cos^2 55/tan 5 tan 1...
sec
(
90
θ
)
.
cosec
θ
 
 
tan
(
90
θ
)
cot
θ
 
+
 
cos
2
35
 
+
 
cos
2
55
 
+
 
tan
5
tan
 
15
tan
45
tan
75
tan
85
=
cosec
 
θ
 
.
cosec
 
θ
 
 
cot
 
θ
 
.
 
cot
 
θ
 
+
 
cos
2
(
90
55
)
+
cos
2
55
 
+
 
tan
(
90
85
)
tan
(
90
75
)
.
1
.
tan
75
tan
85
=
(
cosec
2
θ
 
 
cot
2
θ
)
 
+
 
(
sin
2
55
 
+
 
cos
2
55
)
 
+
 
cot
 
85
 
cot
 
75
 
tan
 
75
 
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85
=
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+
 
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85
 
 
1
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=
3
Community Answer
Evaluate Sec 90-theta cosec-tan 90-theta cos^2 35 cos^2 55/tan 5 tan 1...
Evaluation of Trigonometric Expression

Given Expression:

sec(90-θ) cosec(θ) tan(90-θ) cos² 35° cos² 55° / tan 5° tan 15° tan 45° tan 75° tan 85°


Solution:

Let's simplify the given expression using the trigonometric identities:


Step 1: Simplify the first term

sec(90-θ) = cos(θ)


Step 2: Simplify the second term

cosec(θ) = 1/sin(θ)


Step 3: Simplify the third term

tan(90-θ) = cot(θ) = 1/tan(θ)


Step 4: Simplify the numerator

cos² 35° cos² 55° = (cos 35° * cos 55°)²


Step 5: Simplify the denominator

tan 5° tan 15° tan 45° tan 75° tan 85° = sin 5° sin 15° sin 45° sin 75° sin 85°


Step 6: Substitute the simplified terms in the given expression

cos(θ) * 1/sin(θ) * 1/tan(θ) * (cos 35° * cos 55°)² / (sin 5° sin 15° sin 45° sin 75° sin 85°)


Step 7: Simplify the expression

cos 35° * cos 55° = (cos 45° + cos 20°)/2

(cos 45° + cos 20°)/2 = (√2/2 + cos 20°)/2


Now, substitute the above value in the numerator:

cos(θ) * 1/sin(θ) * 1/tan(θ) * (√2/2 + cos 20°)² / (sin 5° sin 15° sin 45° sin 75° sin 85°)


Using the identity (a+b)² = a² + 2ab + b²:


(√2/2 + cos 20°)² = 1/2 + √2 cos 20° + cos² 20°


Now, substitute the above value in the numerator:

cos(θ) * 1/sin(θ) * 1/tan(θ) * (1/2 + √2 cos 20° + cos² 20°) / (sin 5° sin 15° sin 45° sin 75° sin 85°)


Using the identity 1/sin(θ) = csc(θ) and 1/tan(θ) = cot(θ):

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Evaluate Sec 90-theta cosec-tan 90-theta cos^2 35 cos^2 55/tan 5 tan 15 tan 45 tan 75 tan 85?
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