Introduction:
Alkanes are hydrocarbons that contain only single covalent bonds between carbon atoms. Alkanes can be synthesized by the reduction of alkyl halides using reducing agents such as LiAlH4, Ph3SnH, and NaBH4. In this response, we will discuss how these reagents differ slightly in their work.

Lithium aluminum hydride (LiAlH4):
LiAlH4 is a strong reducing agent that is commonly used for the reduction of carbonyl compounds, carboxylic acids, and alkyl halides. It is a powerful reducing agent because it can donate four hydride ions (H-) to the substrate, which can reduce the alkyl halide to an alkane. However, LiAlH4 is a highly reactive and potentially explosive compound, so it must be handled with care.

Triphenyltin hydride (Ph3SnH):
Ph3SnH is a milder reducing agent that is commonly used for the reduction of alkyl halides. It is less reactive than LiAlH4 and can donate only one hydride ion per molecule. The reaction with Ph3SnH is more selective and can reduce only the most reactive halides, leaving the less reactive halides untouched.

Sodium borohydride (NaBH4):
NaBH4 is a mild reducing agent that is commonly used for the reduction of carbonyl compounds. It can also be used for the reduction of alkyl halides, but it is not as effective as LiAlH4 or Ph3SnH. NaBH4 can donate only one hydride ion per molecule, which limits its reactivity.

Differences in their work:
- LiAlH4 is a strong reducing agent and can reduce a wide range of substrates, including alkyl halides. Ph3SnH is a milder reducing agent and is more selective in its reduction of alkyl halides.
- LiAlH4 can donate four hydride ions per molecule, while Ph3SnH can donate only one. This makes LiAlH4 a more powerful reducing agent than Ph3SnH.
- NaBH4 is the mildest of the three reducing agents and can donate only one hydride ion per molecule. It is not as effective as LiAlH4 or Ph3SnH in reducing alkyl halides.
- LiAlH4 and Ph3SnH are both highly reactive and potentially explosive compounds that must be handled with care.

Conclusion:
In summary, LiAlH4, Ph3SnH, and NaBH4 are all reducing agents that can be used for the reduction of alkyl halides to form alkanes. LiAlH4 is a strong reducing agent that can reduce a wide range of substrates, while Ph3SnH is a milder reducing agent that is more selective in its reduction of alkyl halides. NaBH4 is the mildest of the three reducing agents and is not as effective in the reduction of alkyl halides.

1.LiAlh4 can reduce only 1•,2• degree halides to give alkanes as byproduct.
2.NaBh4 can reduce only 3• alkyl halides to give alkane as byproduct.
3. Ph3Sn4 can reduces all 1•,2•,3• alkali halide to give alkane as byproduct.
e.g # if we have given 3• halide and reagent is LiAlh4 then rxn will stop on alkene bcos it can reduce 3• alkyl halide to yield alkane