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There are two loops A and B placed coaxially along vertical line. Loop A is allowed to fall freely towards loop B. If constant current flowing in loop A is as shown in the figure, then find the direction of flow of induced current in loop B as seen from the bottom of loop B?
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There are two loops A and B placed coaxially along vertical line. Loop...
Direction of induced current in loop B

Induced current is the result of Faraday's law of electromagnetic induction, which states that a change in magnetic field induces an electromotive force (EMF) in a closed loop. The direction of the induced current can be determined using Lenz's law, which states that the induced current will flow in a direction that opposes the change in magnetic field.

Loop A falling towards Loop B

In this scenario, Loop A is falling freely towards Loop B. As Loop A moves closer to Loop B, the magnetic field through Loop B will change. Let's analyze the situation step by step to determine the direction of the induced current in Loop B.

1. Initial position: Before Loop A starts falling, the magnetic field through Loop B is constant. No change in magnetic field means no induced current in Loop B.

2. Loop A starts falling: As Loop A starts to fall, it moves closer to Loop B. The closer proximity between the two loops will result in an increase in the magnetic field through Loop B. According to Lenz's law, the induced current in Loop B will flow in a direction that opposes this increase in magnetic field.

Direction of induced current in Loop B

To determine the direction of the induced current in Loop B, we can use the right-hand rule. If we consider the direction of the current in Loop A (clockwise as shown in the figure), we can curl our fingers in the direction of the magnetic field produced by Loop A. The thumb will then point in the direction of the induced current in Loop B.

Using this right-hand rule, we can determine that the induced current in Loop B will flow in a counter-clockwise direction as seen from the bottom of Loop B. This counter-clockwise current will generate a magnetic field that opposes the increase in magnetic field caused by the falling of Loop A.

Therefore, the direction of the induced current in Loop B, as seen from the bottom of Loop B, will be counter-clockwise.

Conclusion

When Loop A falls towards Loop B, the change in magnetic field through Loop B induces an opposing current in Loop B. According to Lenz's law, the induced current flows in a direction that opposes the change in magnetic field. Using the right-hand rule, we can determine that the induced current in Loop B will flow counter-clockwise as seen from the bottom of Loop B.
Community Answer
There are two loops A and B placed coaxially along vertical line. Loop...
Anticlockwise
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There are two loops A and B placed coaxially along vertical line. Loop A is allowed to fall freely towards loop B. If constant current flowing in loop A is as shown in the figure, then find the direction of flow of induced current in loop B as seen from the bottom of loop B?
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There are two loops A and B placed coaxially along vertical line. Loop A is allowed to fall freely towards loop B. If constant current flowing in loop A is as shown in the figure, then find the direction of flow of induced current in loop B as seen from the bottom of loop B? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about There are two loops A and B placed coaxially along vertical line. Loop A is allowed to fall freely towards loop B. If constant current flowing in loop A is as shown in the figure, then find the direction of flow of induced current in loop B as seen from the bottom of loop B? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two loops A and B placed coaxially along vertical line. Loop A is allowed to fall freely towards loop B. If constant current flowing in loop A is as shown in the figure, then find the direction of flow of induced current in loop B as seen from the bottom of loop B?.
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