Two tankers contains 620 liters and 840 liters of diesel respectively....
**Problem Statement:**
- Two tankers contain 620 liters and 840 liters of diesel respectively.
- Find the maximum capacity of a container that can measure the diesel of both the tankers in an exact number of times.
**Solution:**
- To find the maximum capacity of a container, we need to find the common factors of the two given quantities (620 and 840).
- The factors of 620 are: 1, 2, 4, 5, 10, 20, 31, 62, 124, 155, 310, and 620.
- The factors of 840 are: 1, 2, 3, 4, 5, 6, 7, 8, 10, 12, 14, 15, 20, 21, 24, 28, 30, 35, 40, 42, 56, 60, 70, 84, 105, 120, 140, 168, 210, 280, 420, and 840.
- From the above factors, we need to find the common factors of 620 and 840.
- The common factors of 620 and 840 are: 1, 2, 4, 5, 10, 20, and 40.
- Therefore, the maximum capacity of a container that can measure the diesel of both the tankers in an exact number of times is 40 liters.
- We can measure the diesel of the first tanker 620/40 = 15 times and measure the diesel of the second tanker 840/40 = 21 times using a 40-liter container.
**Answer:**
- The maximum capacity of a container that can measure the diesel of both the tankers in an exact number of times is 40 liters.
Two tankers contains 620 liters and 840 liters of diesel respectively....
We take HCF of 620 and 840
by Euclid's division lemma
c=dq+r, 0< />
840=620×1+220
again by Euclid division lemma
620=220×2+180
again by Euclid division lemma
220=180×1+40
again by Euclid division lemma
180=40×4+20
again by Euclid division lemma
40=20×2+0
the HCF is 20
hence we take 20 L capacity object it measure the both tankers.