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In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =
- a)75°
- b)85°
- c)95°
- d)105º
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In fig, O is the centre of the circle, CA is tangent at A and CB is ta...
Solution:- The length of tangents drawn from an external point to the circle are equal.
In the figure, CA and CB are the tangents from external point of a circle and OA and OB are the two radius of a circle.
Draw a line OC, then you will get two triangles OAC and OBC.
In a ∆le AOC and ∆le BOC,
Angle OAC and OBC = 180 degree. Because, these are angles between the radii and tangents. So, there are two right angles.
The value for right angled triangle is 90 degree. Here, you can see both right angled triangle, so 90×2 = 180 degree.
Angle AOB = Angle OAC + Angle OBC - Angle ACB.
Given:- Angle ACB = 75 degree. , Angle OAC and OBC = 90 degree.
Angle AOB = 90 + 90 - 75.
Angle AOB = 180 -75.
Angle AOB =105 degree.
So, option d is correct friend.
In the figure, CA and CB are the tangents from external point of a circle and OA and OB are the two radius of a circle.
Draw a line OC, then you will get two triangles OAC and OBC.
In a ∆le AOC and ∆le BOC,
Angle OAC and OBC = 180 degree. Because, these are angles between the radii and tangents. So, there are two right angles.
The value for right angled triangle is 90 degree. Here, you can see both right angled triangle, so 90×2 = 180 degree.
Angle AOB = Angle OAC + Angle OBC - Angle ACB.
Given:- Angle ACB = 75 degree. , Angle OAC and OBC = 90 degree.
Angle AOB = 90 + 90 - 75.
Angle AOB = 180 -75.
Angle AOB =105 degree.
So, option d is correct friend.
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In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer?.
In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer?.
Solutions for In fig, O is the centre of the circle, CA is tangent at A and CB is tangent at B drawn to the circle. If ∠ACB = 75°, then ∠AOB =a)75°b)85°c)95°d)105ºCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10.
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