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Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the H+ ion concentration in the mixture?
- a)1.11 x 10-4 M
- b)3.7 x 10-4 M
- c)1.11 x 10-3 M
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a ...
The problem is valid only if strong acids are mixed. After mixing equal volumes of three acids, total volume = 3V.
∴ [H^+] after mixing
= 10^−3 x V/3V + 10^−4 x V/3V + 10^−5 x V/3V = 1.11 x 10^−3/3
= 3.7 x10^−4
View all questions of this test
∴ [H^+] after mixing
= 10^−3 x V/3V + 10^−4 x V/3V + 10^−5 x V/3V = 1.11 x 10^−3/3
= 3.7 x10^−4
Most Upvoted Answer
Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a ...
Given:
Equal volumes of three acid solutions with pH 3, 4, and 5 are mixed in a vessel.
To find:
H ion concentration in the mixture.
Explanation:
The pH of a solution is a measure of its acidity or alkalinity. It is defined as the negative logarithm (base 10) of the hydrogen ion concentration (H+).
Mathematically, pH = -log[H+]
Given that the pH of the three acid solutions is 3, 4, and 5, we can determine the hydrogen ion concentration for each solution.
Calculating Hydrogen Ion Concentration:
For pH 3, [H+] = 10^(-3) M
For pH 4, [H+] = 10^(-4) M
For pH 5, [H+] = 10^(-5) M
Mixing the Solutions:
Since equal volumes of the three acid solutions are mixed, the resulting volume will also be the same.
Let the volume of each solution be V.
The total volume of the mixture = 3V
Calculating Total Hydrogen Ion Concentration:
When the solutions are mixed, the hydrogen ion concentrations will add up.
Total [H+] = [H+] (pH 3) + [H+] (pH 4) + [H+] (pH 5)
Total [H+] = 10^(-3) M + 10^(-4) M + 10^(-5) M
Total [H+] = 1.1 x 10^(-3) M
Answer:
The H ion concentration in the mixture is 3.7 x 10^(-4) M. Therefore, the correct answer is option B.
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Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the H+ion concentration in the mixture?a)1.11 x 10-4Mb)3.7 x 10-4Mc)1.11 x 10-3Md)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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