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The diameters of the top and bottom of a bucket are 40 cm and 20 cm respectively. If the depth of the bucket is 12 cm then its volume will be​
  • a)
    8000 cm3
  • b)
    8800 cm3
  • c)
    9000 cm3
  • d)
    4400 cm3
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The diameters of the top and bottom of a bucket are 40 cm and 20 cm re...
Volume = 1/3πh(R² + r² + R*r)
= 1/3*3.14*1.2*(2² + 1² + 2*1)
= 1/3*3.14*1.2*7
= 26.376/3
Volume = 8.792 cu dm ~= 8800 cm3
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Most Upvoted Answer
The diameters of the top and bottom of a bucket are 40 cm and 20 cm re...
Given: Diameter of top = 40 cm, Diameter of bottom = 20 cm and Depth = 12 cm

To find: Volume of the bucket

Formula used: Volume of frustum = 1/3πh (R² + r² + Rr)

where h = height of frustum, R = radius of bottom circle and r = radius of top circle

Explanation:

1. We need to find the radius of the top circle and radius of bottom circle using the given diameters.

Radius of top circle = Diameter/2 = 20 cm

Radius of bottom circle = Diameter/2 = 10 cm

2. Now we can substitute the given values in the formula to find the volume of frustum.

Volume of frustum = 1/3πh (R² + r² + Rr)

= 1/3π x 12 cm x (10 cm² + 20 cm² + (10 cm x 20 cm))

= 1/3π x 12 cm x (100 cm² + 400 cm² + 200 cm²)

= 1/3π x 12 cm x 700 cm²

= 2800π cm³

3. We can approximate the value of π as 22/7 to simplify the calculation.

Volume of frustum = 2800 x 22/7 cm³

= 8800 cm³

Therefore, the volume of the bucket is 8800 cm³.

Hence, option (b) 8800 cm³ is the correct answer.
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Community Answer
The diameters of the top and bottom of a bucket are 40 cm and 20 cm re...
Given:
Diameter of top of the bucket = 40 cm
Diameter of bottom of the bucket = 20 cm
Depth of the bucket = 12 cm

To find:
Volume of the bucket

Solution:
Let us assume the height of the frustum of the bucket to be 'h'.
Then, the radius of the top of the bucket = 20 cm/2 = 10 cm.
And, the radius of the bottom of the bucket = 40 cm/2 = 20 cm.

Using the formula for the volume of frustum, we get:
Volume of bucket = 1/3 πh (r1² + r2² + r1r2)

Here, r1 = 10 cm and r2 = 20 cm

Substituting the values, we get:
Volume of bucket = 1/3 π(12) (10² + 20² + 10×20)
= 1/3 π(12) (500)
= 200 π cm³

Now, we need to find the value of 200π.
Taking π = 3.14 (approx.), we get:
Volume of bucket = 200×3.14 cm³
= 628 cm³ (approx.)

Therefore, the volume of the bucket is 628 cm³ (approx.)

Option (b) 8800 cm³ is not the correct answer.
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