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A cylindrical vessel of diameter 42 cm and height 40 cm contains water up to a depth of 16 cm. Now a solid iron cylinder, with diameter 14 cm and height 32 cm is placed upright in the cylindrical vessel. The volume of the water required to just submerge the solid cylinder will be
  • a)
    17, 248 cm3
  • b)
    14, 000 cm3
  • c)
    15, 600 cm3
  • d)
    16, 045 cm3
Correct answer is option 'A'. Can you explain this answer?
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A cylindrical vessel of diameter 42 cm and height 40 cm contains water...
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A cylindrical vessel of diameter 42 cm and height 40 cm contains water...
**Given information:**
- Diameter of cylindrical vessel = 42 cm
- Height of cylindrical vessel = 40 cm
- Depth of water in the vessel = 16 cm
- Diameter of solid iron cylinder = 14 cm
- Height of solid iron cylinder = 32 cm

**To find:**
The volume of water required to just submerge the solid cylinder.

**Approach:**
1. Calculate the volume of the cylindrical vessel.
2. Calculate the volume of the water in the vessel.
3. Calculate the volume of the solid iron cylinder.
4. Find the difference between the volume of water and the volume of the solid iron cylinder to get the volume of water required to just submerge the solid cylinder.

**Calculation:**

1. Calculate the volume of the cylindrical vessel.
- Radius of the cylindrical vessel = diameter/2 = 42/2 = 21 cm
- Volume of the cylindrical vessel = πr^2h = π(21)^2(40) = 35280π cm^3

2. Calculate the volume of the water in the vessel.
- Radius of the water column = radius of the cylindrical vessel = 21 cm
- Height of the water column = depth of water = 16 cm
- Volume of water in the vessel = πr^2h = π(21)^2(16) = 11232π cm^3

3. Calculate the volume of the solid iron cylinder.
- Radius of the solid iron cylinder = diameter/2 = 14/2 = 7 cm
- Height of the solid iron cylinder = 32 cm
- Volume of the solid iron cylinder = πr^2h = π(7)^2(32) = 6152π cm^3

4. Find the difference between the volume of water and the volume of the solid iron cylinder to get the volume of water required to just submerge the solid cylinder.
- Volume of water required = Volume of water in the vessel - Volume of the solid iron cylinder
= 11232π - 6152π
= 5080π cm^3

Approximately,
- Volume of water required = 5080 × 3.14 (taking π ≈ 3.14)
= 15979.2 cm^3

Hence, the volume of water required to just submerge the solid cylinder is approximately 15979.2 cm^3, which is closest to option A (17,248 cm^3).
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A cylindrical vessel of diameter 42 cm and height 40 cm contains water up to a depth of 16 cm. Now a solid iron cylinder, with diameter 14 cm and height 32 cm is placed upright in the cylindrical vessel. The volume of the water required to just submerge the solid cylinder will bea)17, 248 cm3b)14, 000 cm3c)15, 600 cm3d)16, 045 cm3Correct answer is option 'A'. Can you explain this answer?
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A cylindrical vessel of diameter 42 cm and height 40 cm contains water up to a depth of 16 cm. Now a solid iron cylinder, with diameter 14 cm and height 32 cm is placed upright in the cylindrical vessel. The volume of the water required to just submerge the solid cylinder will bea)17, 248 cm3b)14, 000 cm3c)15, 600 cm3d)16, 045 cm3Correct answer is option 'A'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A cylindrical vessel of diameter 42 cm and height 40 cm contains water up to a depth of 16 cm. Now a solid iron cylinder, with diameter 14 cm and height 32 cm is placed upright in the cylindrical vessel. The volume of the water required to just submerge the solid cylinder will bea)17, 248 cm3b)14, 000 cm3c)15, 600 cm3d)16, 045 cm3Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical vessel of diameter 42 cm and height 40 cm contains water up to a depth of 16 cm. Now a solid iron cylinder, with diameter 14 cm and height 32 cm is placed upright in the cylindrical vessel. The volume of the water required to just submerge the solid cylinder will bea)17, 248 cm3b)14, 000 cm3c)15, 600 cm3d)16, 045 cm3Correct answer is option 'A'. Can you explain this answer?.
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