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1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?
- a)50 ml.
- b)100 mL
- c)200 mL
- d)400 mL
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is ...
equation 1:
PV= n RT
value of RT = PV/n
RT= 100×200/1 = 20000 .........(1)
equation 2:
PV = nRT
value of RT= PV/n
RT = 400×V/2 = 200V .........(2)
as both R And T are constant
we can equate both the equations
we get,
200V=20000
V= 100 ml
PV= n RT
value of RT = PV/n
RT= 100×200/1 = 20000 .........(1)
equation 2:
PV = nRT
value of RT= PV/n
RT = 400×V/2 = 200V .........(2)
as both R And T are constant
we can equate both the equations
we get,
200V=20000
V= 100 ml
Most Upvoted Answer
1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is ...
Given information:
- 1 mole of gas occupies a volume of 200 mL at 100 mm pressure.
- We are asked to find the volume occupied by 2 moles of gas at 400 mm pressure and the same temperature.
We can solve this problem using the ideal gas law equation, which states that the product of pressure (P) and volume (V) is directly proportional to the number of moles of gas (n) and the temperature (T).
The equation can be written as:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
We can rearrange the equation to solve for volume:
V = (nRT) / P
We are given:
P1 = 100 mm
V1 = 200 mL
n1 = 1 mole
We need to find:
V2 = volume for n2 = 2 moles and P2 = 400 mm
Using the equation, we can calculate the volume for 1 mole of gas at 100 mm pressure:
V1 = (n1RT) / P1
V1 = (1 mol * R * T) / 100 mm
Now, we can find the value of R (gas constant) using the given information. The value of R is 0.0821 L·atm/mol·K.
Substituting the values, we get:
V1 = (1 mol * 0.0821 L·atm/mol·K * T) / 100 mm
Simplifying the equation, we get:
V1 = 0.000821 L·atm·K / mm * T
Now, we can calculate the volume for 2 moles of gas at 400 mm pressure:
V2 = (n2RT) / P2
V2 = (2 mol * 0.0821 L·atm/mol·K * T) / 400 mm
Simplifying the equation, we get:
V2 = 0.0004105 L·atm·K / mm * T
Comparing the equations for V1 and V2, we can see that the volume is inversely proportional to pressure. So, as the pressure increases, the volume decreases.
Since the pressure quadruples (from 100 mm to 400 mm), the volume should decrease by a factor of 4 (2^2) for the same number of moles of gas.
Therefore, V2 = V1 / 4 = 200 mL / 4 = 50 mL.
Hence, the correct answer is option B) 100 mL.
- 1 mole of gas occupies a volume of 200 mL at 100 mm pressure.
- We are asked to find the volume occupied by 2 moles of gas at 400 mm pressure and the same temperature.
We can solve this problem using the ideal gas law equation, which states that the product of pressure (P) and volume (V) is directly proportional to the number of moles of gas (n) and the temperature (T).
The equation can be written as:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
We can rearrange the equation to solve for volume:
V = (nRT) / P
We are given:
P1 = 100 mm
V1 = 200 mL
n1 = 1 mole
We need to find:
V2 = volume for n2 = 2 moles and P2 = 400 mm
Using the equation, we can calculate the volume for 1 mole of gas at 100 mm pressure:
V1 = (n1RT) / P1
V1 = (1 mol * R * T) / 100 mm
Now, we can find the value of R (gas constant) using the given information. The value of R is 0.0821 L·atm/mol·K.
Substituting the values, we get:
V1 = (1 mol * 0.0821 L·atm/mol·K * T) / 100 mm
Simplifying the equation, we get:
V1 = 0.000821 L·atm·K / mm * T
Now, we can calculate the volume for 2 moles of gas at 400 mm pressure:
V2 = (n2RT) / P2
V2 = (2 mol * 0.0821 L·atm/mol·K * T) / 400 mm
Simplifying the equation, we get:
V2 = 0.0004105 L·atm·K / mm * T
Comparing the equations for V1 and V2, we can see that the volume is inversely proportional to pressure. So, as the pressure increases, the volume decreases.
Since the pressure quadruples (from 100 mm to 400 mm), the volume should decrease by a factor of 4 (2^2) for the same number of moles of gas.
Therefore, V2 = V1 / 4 = 200 mL / 4 = 50 mL.
Hence, the correct answer is option B) 100 mL.
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1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is ...
Answer ( B ) 100 ml
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1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?a)50 ml.b)100 mLc)200 mLd)400 mLCorrect answer is option 'B'. Can you explain this answer?
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1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?a)50 ml.b)100 mLc)200 mLd)400 mLCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?a)50 ml.b)100 mLc)200 mLd)400 mLCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1 mole of gas occupies a volume of 200 mL at 100 mm pressure. What is the volume occupied by two moles of gas at 400 mm pressure and at same temperature?a)50 ml.b)100 mLc)200 mLd)400 mLCorrect answer is option 'B'. Can you explain this answer?.
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