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A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :
- a)πs
- b)3π / 2 s
- c)2πs
- d)π / 2 s
Correct answer is option 'C'. Can you explain this answer?
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A circular platform is mounted on a frictionless vertical axle. Its ra...
By applying the law of conservation of angular momentum,
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A circular platform is mounted on a frictionless vertical axle. Its ra...
-1 in the clockwise direction. What is the angular velocity of the platform when the man reaches the opposite side?
First, we need to calculate the angular momentum of the system before the man starts walking. Since the platform is initially at rest, its angular momentum is zero. Therefore, the total angular momentum of the system is:
L = 0 + (50 kg)(2 m)(1 ms-1) = 100 kgm2s-1
When the man reaches the opposite side, he has walked a distance of 2πR = 4π m. Since he is moving at a constant speed, his angular displacement during this time is:
θ = s/R = (4π m)/(2 m) = 2π rad
Using the conservation of angular momentum, we can set the initial and final angular momenta equal to each other:
L = Iω
where ω is the angular velocity of the platform. Solving for ω, we get:
ω = L/I = (100 kgm2s-1)/(200 kgm2) = 0.5 rad/s
Therefore, the angular velocity of the platform when the man reaches the opposite side is 0.5 rad/s.
First, we need to calculate the angular momentum of the system before the man starts walking. Since the platform is initially at rest, its angular momentum is zero. Therefore, the total angular momentum of the system is:
L = 0 + (50 kg)(2 m)(1 ms-1) = 100 kgm2s-1
When the man reaches the opposite side, he has walked a distance of 2πR = 4π m. Since he is moving at a constant speed, his angular displacement during this time is:
θ = s/R = (4π m)/(2 m) = 2π rad
Using the conservation of angular momentum, we can set the initial and final angular momenta equal to each other:
L = Iω
where ω is the angular velocity of the platform. Solving for ω, we get:
ω = L/I = (100 kgm2s-1)/(200 kgm2) = 0.5 rad/s
Therefore, the angular velocity of the platform when the man reaches the opposite side is 0.5 rad/s.
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A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer?.
A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer?.
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A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A circular platform is mounted on a frictionless vertical axle. Its radius R = 2 m and its moment of inertia about the axle is 200 kgm2. It is initially at rest. A 50 kg man stands on the edge of the platform and begins to walk along the edge at the speed of 1 ms–1 relative to the ground. Time taken by the man to complete one revolution is :a)πsb)3π/ 2 sc)2πsd)π/ 2 sCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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