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The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is
    Correct answer is '5'. Can you explain this answer?
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    Analysis:

    Given compound:
    3-bromo-3-cyclopentylhexane

    Reaction:
    Dehydrobromination using alcoholic KOH

    Total number of alkenes:
    5

    Explanation:

    Step 1:
    Identify the starting compound - 3-bromo-3-cyclopentylhexane.

    Step 2:
    Determine the possible alkene products formed by dehydrobromination using alcoholic KOH.

    Step 3:
    Possible products:
    1. 1-cyclopentyl-1-hexene
    2. 2-cyclopentyl-1-hexene
    3. 3-cyclopentyl-1-hexene
    4. 4-cyclopentyl-1-hexene
    5. 5-cyclopentyl-1-hexene

    Step 4:
    Calculate the total number of alkenes by dehydrobromination - 5 in total.
    Therefore, the total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane using alcoholic KOH is 5.
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    The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane usingalcoholic KOH isCorrect answer is '5'. Can you explain this answer?
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    The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane usingalcoholic KOH isCorrect answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane usingalcoholic KOH isCorrect answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The total number of alkenes possible by dehydrobromination of 3-bromo-3-cyclopentylhexane usingalcoholic KOH isCorrect answer is '5'. Can you explain this answer?.
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