There are 5 boys standing in a row and 5 girls are to be paired with t...
So that gives 5x4x3x2 = 120 possible ways to pair up 5 boys and 5 girls into boy-girl couples. Putting the boys in a fixed row, any permutation of the girls will make a valid pairing. So in total there will be 5!= 120 different ways to arrange boy-girl pairs.
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There are 5 boys standing in a row and 5 girls are to be paired with t...
For a group dance, there should be 5 pairs, each having 1 boy and 1 girl.. Let us fix a boy B1,for him we can choose 1 girl among 5 girls in 5 ways. Similarly 4 ways to choose the second one. Hence we will get 5*4*3*2*1 = 120 ways...
There are 5 boys standing in a row and 5 girls are to be paired with t...
Problem Solving Approach:
The given problem is an example of permutation. We need to find the number of ways in which 5 girls can be paired with 5 boys for a group dance competition in a school.
Solution:
The total number of ways in which 5 girls can be paired with 5 boys is given by the permutation formula:
nPr = n! / (n - r)!
where n is the total number of items and r is the number of items to be selected.
In this case, we have 5 girls to be paired with 5 boys, so n = 5 and r = 5.
Therefore,
nPr = 5! / (5 - 5)!
= 5! / 0!
= 5!
= 120
Therefore, there are 120 ways in which 5 girls can be paired with 5 boys for a group dance competition in a school.
Hence, the correct answer is option B.