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The sum and product of the zeroes of the polynomial f(x) = 4x2−27x+3k2 are equal, then the value of ‘k’ is
  • a)
    ±3
  • b)
    0
  • c)
    ±2
  • d)
    ±1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The sum and product of the zeroes of the polynomialf(x) = 4x2−27...
Let α,β are the zeroes of the given polynomial.
Given: 
 ⇒ −(−27) = 3k⇒ k2 = 0 ⇒ k= ±3
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The sum and product of the zeroes of the polynomialf(x) = 4x2−27...
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