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Two A.Ps. have the same common difference. The difference between their 100th terms is 100, what is the difference between their 1000th terms?
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Understanding the Problem
In this scenario, we have two Arithmetic Progressions (A.P.s) with the same common difference. Let's denote the first A.P. as:
- First A.P.: a, a + d, a + 2d, ...
And the second A.P. as:
- Second A.P.: b, b + d, b + 2d, ...
Where:
- 'a' and 'b' are the first terms of the first and second A.P. respectively.
- 'd' is the common difference.
Finding the 100th Terms
The formula for the nth term of an A.P. is given by:
- nth term = first term + (n - 1) * common difference
Thus, the 100th terms can be expressed as follows:
- 100th term of the first A.P.: a + 99d
- 100th term of the second A.P.: b + 99d
According to the problem, the difference between their 100th terms is 100:
- (a + 99d) - (b + 99d) = 100
This simplifies to:
- a - b = 100
Finding the 1000th Terms
Now, let's find the 1000th terms of both A.P.s:
- 1000th term of the first A.P.: a + 999d
- 1000th term of the second A.P.: b + 999d
The difference between their 1000th terms is:
- (a + 999d) - (b + 999d)
This simplifies to:
- a - b = (a - b) + 0 = 100
Conclusion
The difference between the 1000th terms of both A.P.s is also 100.
Thus, the answer is:
- The difference between their 1000th terms is 100.
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Two A.Ps. have the same common difference. The difference between their 100th terms is 100, what is the difference between their 1000th terms?
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